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4 years ago

Trapezoid JKLM is shown on the coordinate plane below:

Mathematics

1 answer:

ololo11 [35]4 years ago

3 0

Answer:

( 1, -4)

Step-by-step explanation:

To find this answer you go over 2 to the right on the x-axis, then go down 6 on the y-axis. This gives ( 1, -4).

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What is the most reasonable for the weight of a table and four chairs? A 19 pounds B 90 pounds C 900 pounds D 9 tons

Rom4ik [11]

Answer:

B. 90 pounds.

Step-by-step explanation:

19 pounds would be too light, 900 pounds would be too heavy, and 9 tons is equal to 18,000 pounds which is wayy too heavy.

Hope this helps!

7 0

3 years ago

Please answer the picture

dimaraw [331]

The area is equal to 230 CM.
area for rectangle :
area = width times length
area = 7 x 20 = 140CM
area for triangle:
area = 1/2 times base times height
area = 1/2 x 20 x 9 = 90CM

ADD:
140+90 = 230 CM

3 0

3 years ago

Read 2 more answers

Sarah paid a food bill of $13.74 with a $20 bill. How much change was she owed? A. $6.74 B. $5.26 C. $6.26 D. $33.74

zhenek [66]

Change = $20 - $13.74 = $6.26

3 0

3 years ago

Read 2 more answers

Solve for <br> (6x + 9)/3 =

hammer [34]

Hello!

(6x + 9)/3 =

= 3(2x + 3)/3 =

= 2x + 3

Good luck! :)

3 0

3 years ago

A sample of size 6 will be drawn from a normal population with mean 61 and standard deviation 14. Use the TI-84 Plus calculator.

AVprozaik [17]

Answer:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean". The letter $\phi(b)$ is used to denote the cumulative area for a b quantile on the normal standard distribution, or in other words: $\phi(b)=P(z$

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

$X \sim N(61,14)$

Where $\mu=61$ and $\sigma=14$

Since the distribution for X is normal then the distribution for the sample mean $\bar X$ is also normal and given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

$\mu_{\bar X} = 61$

$\sigma_{\bar X}= \frac{14}{\sqrt{6}}= 5.715$

So then is appropiate use the normal distribution to find the probabilities for $\bar X$

8 0

3 years ago