x
---- = 5 (solve for x)
0.6
x = 5(0.6)
x = 3
then....
3
----- = 15
0.2
your answer should be 15 ft per second.
hope this helps :)
Answer:
ALLL OF THEM 12
Step-by-step explanation:
Formula to find the arc length is:
Where, s= arc length,
r = radius of the circle
\theta = central angle in degrees.
According to the given problem, \theta= 150 and r =2.4.
So, first step is to plug in these values in the above formula to get the arc length.
=
So, arc length is 
.
Here you're being asked to find the "perimeter" of the space, even tho' the problem doesn't specifically ask for it.
The formula for P is P = 2W + 2L.
Here the width, W, is 3 1/2 yds, and the length, L, is 4 2/3 yds. Subbing these two values into the formula for P (above) results in:
P = 2(3 1/2 yds) + 2(4 2/3 yds)
= 7 yds + 9 1/3 yds = 16 1/3 yds, total.
