Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
1. 3/4
2. im not sure if it means after taking away 3/4, but if it is, its 10/4
x=10/4 and -30/4 i believe, im not too good with fractions, sorry if its wrong :((
Answer:
-3-(-7)
when subtracting a negative the signs turn in to addition
-3+(+7)
4
Step-by-step explanation:
Answer:
42
Step-by-step explanation:
HIJK IS increased by a factor of 3/4 to formH'I'J'K'
so every side is increased by a factor of 3/4
so,Side J'K'=24+24×3/4=42
