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lozanna [386]
3 years ago
9

Help help help please using the elimination solve this​

Mathematics
1 answer:
serious [3.7K]3 years ago
3 0

Answer:

a = 15

b = -14

Step-by-step explanation:

Here, we want to solve by elimination

let us start by rewriting the first equation

We can do this by multiplying through by 10

We have this as;

2a -5b = 100

Now let us eliminate

Multiply equation ii by 2 and equation i by 1

2a -5b = 100

2a-2b = 58

Subtract equation ii from i

-3b = 42

b = 42/-3 = -14

Secondly;

Multiply equation ii by 5 and i by 1

2a - 5b = 100

5a -5b = 145

Subtract ii from i

-3a = -45

a = 45/3

a = 15

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A line passes through the points (1.4) and (2, 2). What is the equation of this line?
emmasim [6.3K]

Answer:

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Step-by-step explanation:

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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the dis
Arte-miy333 [17]
One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.

TimeA = 2.4h (time of Car A to travel)
TimeB = 4h (time of Car B to travel)
SpeedA = SpeedB + 22mph (Speed of Car A<span>)
</span>SpeedB = SpeedA - 22mph (Speed of Car B<span>)
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We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.

SpeedA * 2.4h = x
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</span>(2.4h * SpeedB) + 52.8miles = x

We also know that:
SpeedB * 4h = x

Since both of these equations are equal to x, we can combine them:
SpeedB * 4h = x = <span>(2.4h * SpeedB) + 52.8miles
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SpeedB = 52.8/1.6 mph = 33 mph

<span>SpeedA = SpeedB + 22mph = 33mph + 22mph = 55mph
</span>
Therefore, Car A was traveling at 55mph.
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