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CaHeK987 [17]
3 years ago
5

Can someone show me how to do the problem ? If I take 8 pills a week, how many months is that?​

Mathematics
1 answer:
stiv31 [10]3 years ago
4 0

Answer:

32

Step-by-step explanation:

I assume you want to find the pills per month?  You know that you take 8 pills per week, and there are 4 weeks in a month.  So:

8 pills/week × (4 week / month) = 32 pills/month

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7 0
3 years ago
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The shark are fed three times a day during the morning feeding 2/15 of a ton. During the afternoon feeding the weight of fish fe
UNO [17]

Answer:

The shark are fed \frac16 \ ton of fish during the night.

Step-by-step explanation:

Given:

Weight of fish fed in the morning = \frac{2}{15}\ ton

Also Given:

During the afternoon feeding the weight of fish fed will be 1/15 of a ton more than the fish fed during the morning.

Weight of fish fed in the afternoon = \frac{2}{15}+\frac{1}{15}=\frac{2+1}{15}=\frac{3}{15}\ ton

Total fish fed in whole day = \frac12 \ ton

We need to find the Weight of fish fed in the night.

Solution:

Now we can say that;

Weight of fish fed in the night can be calculated by by subtracting Weight of fish fed in the morning and Weight of fish fed in the afternoon from Total fish fed in whole day .

framing in equation form we get;

Weight of fish fed in the night = \frac{1}{2}-\frac{2}{15}-\frac{3}{15}= \frac{1}{2}-(\frac{2}{15}+\frac{3}{15})=\frac{1}{2}-\frac{2+3}{15}= \frac{1}{2}-\frac{5}{15} = \frac{1}{2}-\frac{1}{3}

Now we will use LCM for making the denominator common we get;

Weight of fish fed in the night = \frac{1\times3}{2\times3}-\frac{1\times2}{3\times2} = \frac{3}{6}-\frac{2}{6}

Now denominator are common so we will solve the numerators.

Weight of fish fed in the night = \frac{3-2}{6}=\frac16 \ ton

Hence The shark are fed \frac16 \ ton of fish during the night.

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3 years ago
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Simplify (3x − 5) − (5x + 1). (2 points)
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5 0
3 years ago
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A public health official is planning for the supplyof influenza vaccine needed for the upcoming flu season. She wants to estimat
Marizza181 [45]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25  

And rounded up we have that n=421

Step-by-step explanation:

We know that the sample proportion have the following distribution:

\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

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The margin of error for the proportion interval is given by this formula:  

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And on this case we have that ME =\pm 0.04 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

We assume that a prior estimation for p would be \hat p =0.5 since we don't have any other info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.04}{1.64})^2}=420.25  

And rounded up we have that n=421

5 0
3 years ago
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