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kenny6666 [7]
3 years ago
15

The uniform crate has a mass of 150 kg. The coefficient of static friction between the crate and the floor is μs = 0.2. The coef

ficient of static friction between the man's shoes and the floor is μ′s = 0.4. Assume the man only exerts a horizontal force on the crate. Determine whether the 85-kg man can move the crate.
Physics
1 answer:
Tatiana [17]3 years ago
3 0

Answer:

The man will be able to move the crate.

Explanation:

\mu_s = Coefficient of static friction between the crate and the floor = 0.2

\mu'_s = Coefficient of static friction between the man's shoes and the floor = 0.4

m_c = Mass of crate = 150 kg

m_p = Mass of man = 85 kg

g = Acceleration due to gravity = 9.81 m/s²

Horizontal force in order to move the crate is given by

F_h=\mu_sm_cg\\\Rightarrow F_h=0.2\times 150\times 9.81\\\Rightarrow F_h=294.3\ N

Maximum force that the man can apply

F_m=\mu'_sm_pg\\\Rightarrow F_m=0.4\times 85\times 9.81\\\Rightarrow F_m=333.54\ N

Here it can be seen that F_m>F_h.

So, the man will be able to move the crate.

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13.5 A = 13.5 C per second
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3 years ago
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E = <u>kQ</u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u>

(r + h)²

where,

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r = 8 × 10^ -2m

h = 16 × 10^ -2m

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E = <u>9</u><u>e</u><u>9</u><u> </u><u>*</u><u> </u><u>3</u><u>0</u><u>0</u><u>e</u><u>^</u><u>-</u><u>6</u><u> </u><u> </u><u> </u><u> </u>

(8e^-2 + 16e^-2)²

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