Answer:
4. 7.59276
Explanation:
Add up the x components:
Aₓ + Bₓ + Cₓ = 5 − 1.6 + 2.4 = 5.8
Add up the y components:
Aᵧ + Bᵧ + Cᵧ = -2.4 + 3.3 + 4 = 4.9
Use Pythagorean theorem to find the magnitude:
√(x² + y²)
√(5.8² + 4.9²)
√57.65
7.59276
Answer:
See below
Explanation:
Photosynthesis is the process in which green plants use sunlight to make their own food. Photosynthesis requires sunlight, chlorophyll, water, and carbon dioxide gas. It is the process in which the chlorophyll in the leaves of the plant use the sunlight and water to convert the carbon dioxide gas into energy for the plant to use.
Answer:
18.63 N
Explanation:
Assuming that the sum of torques are equal
Στ = Iα
First wheel
Στ = 5 * 0.51 = 3 * (0.51)² * α
On making α subject of formula, we have
α = 2.55 / 0.7803
α = 3.27
If we make the α of each one equal to each other so that
5 / (3 * 0.51) = F2 / (3 * 1.9)
solve for F2 by making F2 the subject of the formula, we have
F2 = (3 * 1.9 * 5) / (3 * 0.51)
F2 = 28.5 / 1.53
F2 = 18.63 N
Therefore, the force F2 has to 18.63 N in order to impart the same angular acceleration to each wheel.
Explanation:
It is given that,
Displacement of the delivery truck,
(due east)
Then the truck moves,
(due south)
Let d is the magnitude of the truck’s displacement from the warehouse. The net displacement is given by :


d = 4.03 km
Let
is the direction of the truck’s displacement from the warehouse from south of east.


So, the magnitude and direction of the truck’s displacement from the warehouse is 4.03 km, 37.4° south of east.
Answer:
P = 1000000[Pa] = 1000 [kPa]
Explanation:
To solve this problem we must use the definition of pressure, which is equal to the relationship of force over area.

where:
P = pressure [Pa] (units of pascals)
F = force = 100 [N]
A = area = 100 [mm²]
But first we must convert the units from square millimeters to square meters.
![A=100[mm^{2}]*\frac{1^{2} m^{2} }{1000^{2}mm^{2} } =0.0001[m^{2} ]](https://tex.z-dn.net/?f=A%3D100%5Bmm%5E%7B2%7D%5D%2A%5Cfrac%7B1%5E%7B2%7D%20m%5E%7B2%7D%20%7D%7B1000%5E%7B2%7Dmm%5E%7B2%7D%20%20%7D%20%3D0.0001%5Bm%5E%7B2%7D%20%5D)
Now replacing:
![P=100/0.0001\\P=1000000[Pa]](https://tex.z-dn.net/?f=P%3D100%2F0.0001%5C%5CP%3D1000000%5BPa%5D)