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olganol [36]
2 years ago
10

When an object is placed 30.0 cm in front of a concave mirror, a real image is formed 60.0 cm

Physics
1 answer:
Marrrta [24]2 years ago
3 0

Answer:

1 / f = 1 / o + 1 / i = (i + o) / o * 1

f = o * i / (o + i) = 60 * 30 / (60 + 30) = 1800 / 90 = 20 cm

Both the object and image are in positive space for a mirror

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Suppose an asteroid had an orbit with a semimajor axis of 4 au. how long would it take for it to orbit once around the sun?
Nitella [24]

It would take <u> 8 years </u> for the asteroid to orbit once around the sun.

What is a semimajor axis?

  • In geometry, the major axis of an ellipse is its longest diameter: a line segment that runs through the center and both foci, with ends at the two most widely separated points of the perimeter.
  • The semi-major axis (major semiaxis) is the longest semidiameter or one half of the major axis, and thus runs from the centre, through a focus, and to the perimeter.
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5 0
1 year ago
Direct current made it possible to distribute electric power over greater areas.
Mademuasel [1]
True, I'm not the best when it comes to science, but I'm pretty sure it's this
3 0
3 years ago
What device increases voltage?
erma4kov [3.2K]

Your answer would be C.

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Hope this helps; have a great day!

8 0
3 years ago
What type of acceleration does an object moving with constant speed in a circular path experience?Select one:A) constant acceler
olga_2 [115]

ANSWER:

D) centripetal acceleration.

STEP-BY-STEP EXPLANATION:

When a body performs a uniform circular motion, the direction of the velocity vector changes at every instant. This variation is experienced by the linear vector, due to a force called centripetal, directed towards the center of the circumference that gives rise to the centripetal acceleration.

Therefore, the answer is centripetal acceleration.

3 0
1 year ago
A steel bar of rectangular cross section (1.5 in. 2 3 .0 in.) carries a tensile load P (see fig- ure). The allowable stresses in
lukranit [14]

Explanation:

Value of the cross-sectional area is as follows.

        A = 1.5 \times 2.30

           = 3.45 in^{2}

The given data is as follows.

          Allowable stress = 14,500 psi

          Shear stress = 7100 psi

Now, we will calculate maximum load from allowable stress as follows.

           P_{max} = \sigma_{a}A

                       = 14500 \times 3.45

                       = 50025 lb

Now, maximum load from shear stress is as follows.

           P_{max} = 2 \times \tau_{a} \times A

                      = 2 \times 7100 \times 3.45

                      = 48990 lb

Hence, P_{max} will be calculated as follows.

       P_{max} = min((P_{max})_{\sigma}, (P_{max})_{\tau})

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Thus, we can conclude that the maximum permissible load P_{max} is 48990 lb.

4 0
3 years ago
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