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dalvyx [7]
3 years ago
11

Sonar signals and infrared light are are used to send messages to submarines deep under water. If we compare the two signals, wh

ich statement describes a difference between the two?
Chemistry
2 answers:
murzikaleks [220]3 years ago
6 0
Do you have the statements for it that might help us get you the answer?
sesenic [268]3 years ago
5 0

b  The infrared light gets there faster and is clearer.

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If you see the Sun is high in the sky, what can you say about the SUN as viewed from the opposite side of Earth at the same mome
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HELP ME PLEASE!!!! what part of a wind turbine provides motion to convert into electricity?
FrozenT [24]

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3 0
4 years ago
A groundwater (GW) was analyzed for ions and the results are reported below: Ca2+ = 200 mg/L (as Ca2+) Mg2+ = 60 mg/L (as Mg2+)
garri49 [273]

Answer:

Answer is given below.

Explanation:

<em />

<em>Alkalinity = 400 mg/L in terms of CaCO3  </em>

<em>a.) Total Hardness is defined as the sum of calcium and magnesium iion concentration in terms of CaCO3 </em>

<em> </em>

<em>Total Hardness = [Ca+2]*{50/20) + [Mg+2]*{50/12) = [200]*{50/20) + [60]*{50/12) = 750 mg/L in terms of CaCO3 </em>

<em> </em>

<em>b.) Non-Carbonate hardness = Total Hardness - Carbonate Hardness </em>

<em> </em>

<em>Now here as the Total Hardness is greater than alkalinity ,Thus </em>

<em> </em>

<em>Carbonate Hardness = Alkanlinity = 400 mg/L in terms of CaCO3 </em>

<em> </em>

<em>Non-Carbonate hardness = 750 - 400 = 350 mg/L in terms of CaCO3 </em>

<em> </em>

<em>c.) As Total hardness is greater than Alkalinity thus Carbonate hardness is equal to the Alkalinity. </em>

<em> </em>

<em>Carbonate hardness = 400 mg/L in terms of CaCO3 </em>

<em> </em>

<em>d.) Now as the Total hardness of the ground water is more than 180 mg/L,Thus it needs removal of hardness. </em>

<em> </em>

<em>There are many treatment options for the removal of hardness: </em>

<em>i) Ion Exchange method </em>

<em>ii) Lime soda method</em>

5 0
3 years ago
the density of dry air at 20 degrees celsius is 1.20 g/L. What is the mass of air, in kilograms, of a room that measures 24.0m b
nika2105 [10]

Answer:

1728 kg is the mass of air for the room

Explanation:

An exercise of unit conversion.

The volume of the room will be:

24 m . 15 m . 4m = 1440 m³

Density of air is 1.20 g/L which means that in 1L, there is contained 1.20 g of air.

1L = 1dm³

1m³ = 1000 dm³

1440 m³ . 1000 = 1440000 dm³ ⇒ 1.44x10⁶ L

Density of air = 1.20 g/L = mass of air / volume of air

1.20 g/L = mass of air / 1.44x10⁶ L

1.20 g/L  . 1.44x10⁶ L = mass of air →  1728000 grams

1 g = 1x10⁻³ kg

1728000 g / 1000 = 1728 kg

7 0
3 years ago
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