Question

Please help!!!! I need an answer quick!!!

Answer 1

Answer:

16.7 g of acetate

Explanation:

Molarity (mol/L), a sort of concentration that indicates the moles of solute in 1 L of solution.

We have the solution's volume, so let's convert it to L

300 mL . 1L/1000mL = 0.3 L

Molarity = mol/ vol(L)

Molarity . vol(L) = moles → 0.243 M . 0.300L = 0.0729moles

Chromium (III) acetate = Cr(CH₃COO)₃ → Molar mass = 229 g/mol

We convert the moles to mass (moles . molar mass) =  0.0729 mol . 229 g/mol = 16.7 g

Answer 2

Answer:

The answer to your question is  16.7 g of Cr(CH₃COO)₃

Explanation:

Data

Concentration = 0.243 M

Volume = 300 ml

mass of Chromium (III) acetate = ?

Process

1.- Write the formula of the compound

               Cr(CH₃COO)₃

2.- Calculate the molar mass of the compound

Cr(CH₃COO)₃ = 52 + (6 x 12) + (9 x 1) + (6 x 16)

                       = 52 + 72 + 9 + 96

                       = 229 g

3.- Determine the number of moles

Molarity = moles /volume

Moles = Molarity x volume

Moles = 0.243 x 0.300

Moles = 0.0729

4.- Calculate the grams of chromium (III) acetate

                      229 g ------------------ 1 mol

                         x      ----------------- 0.0729 mol

                         x = (0.0729 x 229) /1

                         x = 16.7 g of Cr(CH₃COO)₃