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AlexFokin [52]
3 years ago
9

46 ÷ 8=6.75 What part of this problem needs to be changed to make it correct?

Mathematics
1 answer:
scoray [572]3 years ago
5 0
46 / 8 = 5.75 not 6.75
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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
3 years ago
What is 4/20 + 11/20 in its simplest form​
vivado [14]

Answer:

Step-by-step explanation:

4/20 + 11/20 = 15/20

15/20 = 3/4 or 0.75

6 0
3 years ago
Read 2 more answers
Find the area of the given triangle.
yan [13]
Area of triangle = base x height over 2
3 x 4 = 12
12 over 2 = 6
area = 6cm^2
5 0
3 years ago
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Three fourths divided by one eighths
Ilya [14]
3/4÷1/8 is the same as 3/4×8/1.
3×8=24
4×1=4
That becomes 24/4 which simplifies to 6. Your answer is 6.
4 0
3 years ago
The value of y when x=5
Molodets [167]
D. 35 is the answer. Since we know that 14=2k based on the knowledge given in the first part of the equation, we can solve for K. We learn that K=7. Then, we can substitute K into the second equation: y=(7)(5) which is 35.
8 0
3 years ago
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