Answer:
Balanced equation is: 2Na (s) + Cl₂(g) → 2NaCl (s)
Number of moles of needed Cl₂ → 0.217 moles
Mass of needed Cl₂ → 15.4 g
Explanation:
We determine the reaction
2Na (s) + Cl₂(g) → 2NaCl (s)
We convert the mass of solid Na to moles
10 g. 1 mol/23 g = 0.435 moles
Ratio is 2:1. 2 moles of Na react with 1 mol of chlorine
Then, 0.435 moles of Na may react with (0.435 . 1)/2 = 0.217 moles of Cl₂
Number of moles of needed Cl₂ → 0.217 moles
We convert the moles to mass → 0.217 mol . 70.9 g/1mol = 15.4 g
