If one of our zeros is 4, then the factor is x-4. If the second zero is 5i, then the conjugate root theorem says there HAS to be a root that is -5i. So our 3 factors are (x-4)(x+5i)(x-5i). We will FOIL out these factors to get the polynomial. Let's start with the ones that contain the imaginary numbers. Doing that mutliplication we get x^2-25i^2. i^2 is equal to -1, so what that expression simplifies down to is
. Now we will multiply in that last factor of (x-4):
. FOILing out we have
. There you go!
Answer:
y-2 = 5(x-3)
Step-by-step explanation:
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Hope that helps
I'm struggling thinking about whether or not this is a real question or if you just wanna talk about BTS XD
1.) Solve for length b.
The simpler method is to use the Pythagorean theorem. If 
, then this means that 
.
Plug in the values:
--> 
So this means that b is the square root of 72, which is 8.49
2.) Solve for ∠A.
Let's refer to the law of sines. If 
, then this means we can cross multiply. Since A is the value we are solving for, the equation should be written out like this:
--> 
A is 39.52°
3.) Solve for ∠B.
This is the easiest one. The sum of all three angle measures in a triangle add up to 180°. We already know that one of the angles is a right angle and the other 39.52°.
39.52 + 90 = 129.52
180 - 129.52 = 50.48
∠B is 50.48°.
All of the following are acute angles.
