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Alborosie
3 years ago
6

I can't figure this out help.

Mathematics
1 answer:
olga_2 [115]3 years ago
4 0

Answer:

33+.58=33.58mm to the third power

Step-by-step explanation:

I did the problem I the answer spot

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Use one or more transformations to transform the pre-image (purple) onto the image (white).
balandron [24]

Answer:  This is a translation of 12 units to the right.

translation written (x,y) -> (x+12,y+0)

Step-by-step explanation:

Pick a point on the pre-image, and count how many squares it has to move to end up at the corresponding point in the image.

Add that value to the coordinate x  for horizontal movement, here +12.

Add to the coordinate y for vertical movement. here 0.

8 0
3 years ago
A line passes through the point A(5/6​,−7) and has a slope of 3. Using the point-slope formula, express the equation of the line
Lisa [10]

Answer:

a;dnw

Step-by-step explanation:

4 0
3 years ago
20 POINTS. Use a ratio box to solve the problem. The ratio of carnivores to herbivores is 2 to 7. If there were 126 carnivores i
nignag [31]

Answer:

Step-by-step explanation:

\frac{herbivores}{carnivores}=\frac{7}{2} \\\\\frac{x}{126} =\frac{7}{2} \\x=\frac{7}{2} *126=441

8 0
3 years ago
49°<br> Solve for 42.<br> 2 = [?]<br> 44/62
Brrunno [24]

Answer:

∠2 = 41°

Step-by-step explanation:

∠2 + 49° + 90° = 180°

∠2 + 139° = 180°

∠2 = 180° - 139°

∠2 = 41°

5 0
3 years ago
Read 2 more answers
Consider the expansion of (5p + 2q)^6. Determine the coefficients for the terms with the powers of p and q shown.
Step2247 [10]

Answer:

Remember, the expansion of (x+y)^n is (x+y)^n=\sum_{k=0}^n \binom{n}{k}x^{n-k}y^k, where \binom{n}{k}=\frac{n!}{(n-k)!k!}.

Then,

(5p+2q)^6=\sum_{k=0}^6\binom{6}{k}(5p)^{6-k}(2q)^k=\sum_{k=0}^6\binom{6}{k}5^{6-k}2^k p^{6-k}q^k

Then, the coefficient of the term p^{6-k}q^k is \binom{6}{k}5^{6-k}2^k

a) since 6-k=2, then k=4. So the coefficient of p^2q^4 is

\binom{6}{4}5^{6-4}2^4=15*5^2*2^4=15*25*16=6000

b) since 6-k=5, then k=1. So, the coefficient of p^5q is

\binom{6}{1}5^{6-1}2^1=6*5^5*2=37500

c) since 6-k=3, then k=3. So, the coefficient of p^3q^3 is

\binom{6}{3}5^{6-3}2^3=20*5^3*8=20000

6 0
3 years ago
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