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IceJOKER [234]
4 years ago
10

a local hamburger shop soda combined order of 497 hamburgers and cheeseburgers on Friday there was 53 fewer cheeseburgers sold t

han hamburgers how many hamburgers were sold on Friday
Mathematics
1 answer:
BartSMP [9]4 years ago
5 0

Answer:

you need a answer I can see 425

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Expand and simplify (2x−12) ^2
lubasha [3.4K]

Answer:

\boxed{4x^{2}  - 48x + 144}

Step-by-step explanation:

Given expression:

  • (2x - 12)²

To simplify the expression, we will use the formula (a - b)² = a² - 2ab + b².

[Where "a and b" are the first and second term in (a - b)²]

\rightarrowtail (2x - 12)^{2}

In this case, the first term of (2x - 12)² is "2x" and the second term is "12".

\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2} \ \ \ \ \ \ \ \ \ \ \ \ \ \  [\small\text{First term = a = 2x; Second term = b = 12]}

Now, simplify the expression.

\rightarrowtail (2x)^{2} - 2(2x)(12) + (12)^{2}

\rightarrowtail (2x)(2x) - (4x)(12) + (12)(12)

\rightarrowtail \boxed{4x^{2}  - 48x + 144}

4 0
2 years ago
The point (5, -2) is rotated 90° about the origin. Its image is:
OLEGan [10]
If rotated around the origin clockwise the new point is found at (-2,-5)
8 0
3 years ago
What is the value of x in this equation? 5x − 2(2x − 1) = 6
MakcuM [25]

Answer:

x=4

Step-by-step explanation:

5x-4x+2=6

x+2=6

x=6-2

x=4

7 0
3 years ago
Read 2 more answers
I need help ASAP because I need done before 4:00pm
Naddik [55]

Answer:

the 13th one is 115

Step-by-step explanation:

8 0
3 years ago
How much more would $1,000 earn in 5 years in an account compounded continuously than an account compounded quarterly if the int
s2008m [1.1K]

Answer: There is a difference of $ 1.0228.

Explanation: Given, initial amount or principal = $ 1000,

Time= 5 years and given compound rate of interest = $3.7%

Now, Since the amount in compound continuously,

A= Pe^{rt} , where, r is the rate of compound interest, P is the principal amount and t is the time.

Here, P=$ 1000, t=5 years and r= $3.7%,

Thus, amount in compound continuously ,  A=1000e^{3.7\times5/100}

⇒A=1000e^{18.5}=1000\times 1.20321844013=1203.21844013

Therefore, interest in this compound continuously rate =1203.21844013-1000=203.21844013

now, Since the amount in compound quarterly,

A=P(1+\frac{r/4}{100} )^{4t}, where, r is the rate of compound interest, P is the principal amount and t is the time.

Thus, amount in compound quarterly, A=1000(1+\frac{3.7/4}{100} )^{4\times5}

⇒A=1000(1+\frac{3.7}{400} )^{20}

⇒A=1000(1+\frac{3.7}{400} )^{20}

⇒A= 1202.19567617

Therefore, interest in this compound quarterly rate=1202.19567617-1000=202.19567617

So, the difference in these interests=203.21844013-202.19567617=1.02276396 ≈1.0228                                                  

4 0
3 years ago
Read 2 more answers
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