<h2>
Answer:</h2>
This is easy. All you need to do is set up a <u><em>proportional relationship</em></u>.
A proportional relationship uses variables to show similarities, in this case, in triangles.
<u><em>x</em></u> represents the missing side.
Answer: Choice B
Two and four tenths multiplied by the difference of six and two tenths and a number is more than negative four and five tenths.
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Explanation:
2.4 = 2 + 0.4
2.4 = 2 and 4/10
2.4 = 2 and 4 tenths
2.4 = two and four tenths
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Through similar reasoning,
6.2 = six and two tenths
And also,
-4.5 = negative four and five tenths
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Notice how 6.2 - x translates into "difference of six and two tenths and a number"
We then multiply that by 2.4, aka two and four tenths.
So that's how we get the phrasing "Two and four tenths multiplied by the difference of six and two tenths and a number"
All of this is greater than -4.5 aka negative four and five tenths.
This points us to Choice B as the final answer.
Answer:
Step-by-step explanation:
a) We have 15! as the product of 1 to 15 natural numbers. Since 17 is prime there will be no factor common to these
By actual division we find
15! (mod 17) =16
From this we deduce
even 16! mod 17 = 16 = -1
According to Wilson theorem
(17-1)! = -1 mod 17
Thus verified 17 is prime
Hence 15! (mod 17) =-1=16
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b) 2(26!) is divided by 29
Since 29 is prime
(29-1)! = -1 mod 29
28! = -1 mod 29 = 28
When divided this gives 25 as remainder
<h2>Answer:
81
Step-by-step explanation:
The median of data not grouped is the middle number after arranging the data is either ASCENDING OR DESCENDING order. Arranging these states HIGH TEMPERATURES in ascending order, we have:
72, 78, 79, 81, 81, 82, 84, 88, 88
The middle number there is 81 </h2>
What are you solving for?
If you are solving for × then I hope this helps
Let's solve for x.
f(x)= 100−10+e−0.1x
Step 1: Add 0.1x to both sides.
xf+0.1x=−0.1x+e+90+0.1x
xf+0.1x = e+90
Step 2: Factor out variable x.
x(f+0.1) = e+90
Step 3: Divide both sides by f+0.1.
x(f+0.1)/ f+0.1 =e+90/ f+0.1
x=e+90/ f+0.1
Answer:
x= e+90/ f+0.1
