Answer:
two sets are said to be overlapping if they contain at least one element in common A=(1,2,3,4)and B =(4,7,1,9)are said to be overlapping sets.
Step-by-step explanation:
please answer my question I answer your question
(xii) NH₂ + Cl₂ →→→→NH₂CI+ N₂
(xiv) NaOH + Cl₂ →→ NaCl + NaCIO + H₂O
" (vi) CH, + 0,— CO, + H,0
xviii) C₂H₂ + O₂2 CO₂ + H₂O
(xx) Na + H₂O → NaOH + H₂
A (xxii) PbO₂ PbO + 0₂
xxiv) NH3 + CuO →→→ → N₂ + H₂O + Cu
xxvi) H₂S + Cl₂ →→→ HCI + S
xviii) H₂S + H₂SO4 → H₂O + SO₂ + S
(xxx) C + HNO3 → CO₂ + NO₂ + H₂O
Answer:
10) 9x - 2° = 5x + 54° (corresponding angles are equal)
9x - 5x = 54 + 2
4x = 56
x = 56/4
x = 14°
10y + 6° = 9x - 2° (linear pair)
10y + 6° = 9(14)° - 2°
10y + 6° = 126° - 2°
10y + 6° = 124°
10y = 124° - 6°
10y = 118
y = 118/10
Sorry, i don't know how to do the 11th question
but hope this helps you!
Answer:
B
Step-by-step explanation:
Using the determinant to determine the type of zeros
Given
f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is
Δ = b² - 4ac
• If b² - 4ac > 0 then 2 real and distinct zeros
• If b² - 4ac = 0 then 2 real and equal zeros
• If b² - 4ac < 0 then 2 complex zeros
Given
f(x) = (x - 1)² + 1 ← expand factor and simplify
= x² - 2x + 1 + 1
= x² - 2x + 2 ← in standard form
with a = 1, b = - 2, c = 2, then
b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4
Since b² - 4ac < 0 then the zeros are complex
Thus P(x) has no real zeros
You do 9+3 which equals 12 then you multiply that by 4
Answer:
- 4 < x ≤ 7
Step-by-step explanation:
Given
- 10 ≤ - 5x + 25 < 45 ( subtract 25 from all 3 intervals )
- 35 ≤ - 5x < 20
Divide all 3 intervals by - 5, reversing the inequality signs as a consequence.
7 ≥ x > - 4
Hence - 4 < x ≤ 7
