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marin [14]
2 years ago
14

A rectangular deck is 12 ft by 14 ft. When the length and width are increased by the same amount, the area becomes 288 sq. ft. B

y how much were the dimensions increased?
2 ft
4 ft
8 ft
10 ft
Mathematics
2 answers:
alexdok [17]2 years ago
6 0
To solve this problem you must apply the proccedure shown below:

 1. You have the following information given in the problem above:

 - The<span> rectangular deck has the following dimensions: 12 ft by 14 ft.
 - When the length and width are increased by the same amount, the area becomes 288 ft</span>².

 2. Therefore, you have:

 A=bxh

 288=(12x)(14x)
 288=168x²

 3. When you clear the x, you obtain:

 x=√288/168
 x=(2√21)/7≈1.31
 
Aloiza [94]2 years ago
4 0

Answer:

4 ft option (c)

Step-by-step explanation:

Length of a rectangular deck = 12 ft.

width of rectangular deck= 14 ft.

let the length and width are increased by the x ft.

New length = (12 + x) ft  

New width = (14+ x) ft.

area of rectangular width = length × width

according to the question

(12+x)(14+x) = 288

168+x^{2}=+14x+12x = 288

x^{2}+26x = 228-168

x^{2}+26x-120=0

x^{2}+ 30x-4x-120=0

x(x+30)-4x(x+30)

x=4 or x=-30

x=-30 is rejected

Hence, the length and width are increased by the 4 ft.

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MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

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b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

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so the slope of the terminal ray is

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