This one is easy, Chifa!:) I know this is the right anwser. Plz give me a five-star rating.
Option C: -3 is the average rate of change between
and 
Explanation:
The formula to determine the average rate of change is given by
Average rate of change = 
We need to find the average rate of change between
and 
Thus, from the table, we have,
, 
, 
Thus, substituting these values in the formula, we get,
Average rate of change = 


Thus, the average rate of change between
and
is -3.
Hence, Option C is the correct answer.
Answer:
Cost of one pencil: 
Cost of one eraser: 
Step-by-step explanation:
Let be "p" the cost in dollars of one pencil and "e" the cost in dollars of one eraser.
Based on the information given in the exercise, you can set up the following system of equations:

You can use the Elimination Method to solve the system of equations.
Multiply the first equation by -3 ad the second one by 4. Then add the equations and solve for "e":
{
Substitute the value of "e" into any original equation and solve for "p":

Answer:
Step-by-step explanation:
Statements Reasons
1). Points A, B and C form the triangle 1). Given
2). Let DE be a line passing through 2). Definition of parallel lines
B and parallel to AC
3). ∠3 ≅ ∠5 and ∠1 ≅ ∠4 3). Theorem of Alternate
interior angles
4). m∠1 = m∠4 and m∠3 = m∠5 4). Definition of alternate angles
5). m∠4 + m∠2+ m∠5 = 180° 5). Angle addition and definition
of straight lines
6). m∠1 + m∠2+ m∠3 = 180° 6). Substitution
Let's say the numbers are "a" and "b"
hmm say "a" is the smaller, and "b" the greater
so "b" is "4 more than 5 times" "a"
so... 5 times "a" is 5*a or 5a
4 more than "that", will be "that" + 4
or
5a + 4
so.. whatever "a" is, "b" is 5a+4
now, their sum is 22, as opposed to "zz" hehe
so

solve for "a", to see what the smaller one is
what's "b"? well, b = 5a + 4