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Pepsi [2]
3 years ago
14

In order to solve the equation below, you need to change it around so that n is by itself. Write this new equation. Do not inclu

de any spaces in your answer.
n/6=30
Mathematics
1 answer:
ale4655 [162]3 years ago
6 0
N/6=30
Multiply both sides by 6
n=180
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What is the slope-intercept form of the line passing through the point (2, 1) and having a slope of 4?
patriot [66]

Answer:

1=4(2)-7

Step-by-step explanation:

y=mx+b

b=where it crosses the y-axis

m=slope

1=4(2)-7

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3 years ago
Thea and Eleanor are reading the same book. The graph shows the number of words Thea reads over time. Eleanor reads 225 words pe
Lapatulllka [165]
The slope is the rate
words per minute
we can do
540 words in 3 minutes
divide by 3
180 words in 1 minute

thea=180wpm
elanor=225wpm

elanor>thea

and 225*2=450


answers are
Thea reads 180 words per minute.

Eleanor reads 450 words every 2 minutes.

After 1 hour of reading, Eleanor reads more words than Thea.

6 0
3 years ago
Read 2 more answers
Each small square on the grid is 1 ft squared.
Shalnov [3]
Approximately 50ft because 5 put into the shape would be around 48 and it would be the best estimate of 50
3 0
3 years ago
The points A(1, 4), B(5,1) lie on a circle. The line segment AB is a chord. Find the equation of a diameter of the circle.
tangare [24]

Check the picture below.

well, we want only the equation of the diametrical line, now, the diameter can touch the chord at any several angles, as well at a right-angle.

bearing in mind that <u>perpendicular lines have negative reciprocal</u> slopes, hmm let's find firstly the slope of AB, and the negative reciprocal of that will be the slope of the diameter, that is passing through the midpoint of AB.

\bf A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{5}-\underset{x_1}{1}}}\implies \cfrac{-3}{4} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{slope of AB}}{-\cfrac{3}{4}}\qquad \qquad \qquad \stackrel{\textit{\underline{negative reciprocal} and slope of the diameter}}{\cfrac{4}{3}}

so, it passes through the midpoint of AB,

\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ A(\stackrel{x_1}{1}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{5}~,~\stackrel{y_2}{1}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{5+1}{2}~~,~~\cfrac{1+4}{2} \right)\implies \left(3~~,~~\cfrac{5}{2} \right)

so, we're really looking for the equation of a line whose slope is 4/3 and runs through (3 , 5/2)

\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{\frac{5}{2}}) \stackrel{slope}{m}\implies \cfrac{4}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{\cfrac{5}{2}}=\stackrel{m}{\cfrac{4}{3}}(x-\stackrel{x_1}{3})\implies y-\cfrac{5}{2}=\cfrac{4}{3}x-4 \\\\\\ y=\cfrac{4}{3}x-4+\cfrac{5}{2}\implies y=\cfrac{4}{3}x-\cfrac{3}{2}

4 0
3 years ago
Would you rather (A) Run for 12 minutes at least 10 miles and hour; ... OR ... (B) 20 minutes at 6 miles per hour?
vlabodo [156]
Its actually the same length. I will choose B so that i can run slower
5 0
3 years ago
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