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ozzi
3 years ago
8

A rectangular prism pool has dimensions of 25 feet by 15 feet and is 4 feet deep. If water costs $0.03 per cubic feet, how much

will it cost to fill the pool?
Mathematics
2 answers:
Delicious77 [7]3 years ago
5 0
It would cost 45 dollars
MrRa [10]3 years ago
4 0
Find the volume
V=LWH
L=25
W=15
H=4
V=25*15*4
V=1500 cubic feet

0.03 per 1 cubic foot
0.03 times 1500=45

answer is $45 to fill the pool
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lana66690 [7]

Answer: Third option.

Step-by-step explanation:

Some transformations for a function f(x) are shown below:

If f(x)+k, the function is translated "k" units up

If f(x)-k, the function is translated "k" units down.

If f(x+k), the function is translated "k" units left.

If f(x-k), the function is translated "k" units right.

In this case you have the following function:

f(x)=3x+2

And you know that the function g(x) is obtained by translating the function f(x) 5 units down and 3 units left; therefore, you can conclude that g(x) is:

g(x)=3(x+3)-3

Finally, simplifying, you get that this is:

g(x)=3x+9-3\\\\g(x)=3x+6

5 0
3 years ago
A fair coin and a biased coin where the probability of obtaining a head is twice the probability of obtaining a tail. if both ar
Art [367]

Answer:

See below in bold.

Step-by-step explanation:

For the fair coin Prob(head) = 1/2 and Prob(Tail) = 1/2.

For the biased coin it is   Prob(head) = 2/3 and Prob(Tail) = 1/3.

a) Prob(2 heads) = 1/2 * 2/3 = 1/3.

b) Prob(2 tails) = 1/2 * 1/3 = 1/6.

c) Prob(1 head ) = Prob(H T or T H) = 1/2 * 1/3  + 1/2 * 2/3) = 1/6+1/3 = 1/2.

d) Prob (at least one head) = prob (HH or TH or HT) =  1/3 + 1/2 =<em> </em>5/6.

4 0
3 years ago
For y = 6/x² estimate the value of 6/(4.03)².​
Aleks [24]
=ligma baalls so that I can tape this d to your fore head so you can cd’s nuts
6 0
2 years ago
Use the x-intercept method to find all real solutions of the equation x^3-10x^2+17x+28=0
Alekssandra [29.7K]

A graphing calculator shows the x-intercepts of the expression on the left to be -1, 4, 7.

The real solutions to the cubic equation are x ∈ {-1, 4, 7}.

6 0
3 years ago
Read 2 more answers
Write in simplest form:<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B24a%5E%7B10%7Db%5E%7B6%7D%7D" id="TexFormula1" ti
Charra [1.4K]

Answer:

2a^3b^2\sqrt[3]{3a}

Step-by-step explanation:

Use the following rules for exponents:

a^m*a^n=a^{m+n}\\\\\sqrt[3]{x^3}=x

Simplify 24. Find two factors of 24, one of which should be a perfect cube:

8*3=24\\\\2^3=8

Insert:

\sqrt[3]{2^3*3a^{10}b^6}

Now split the exponents. Split 10 into as many 3's as possible:

10=3+3+3+1

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^6}

Split 6 into as many 3's as possible:

6=3+3

Insert as exponents:

\sqrt[3]{2^3*3*a^3*a^3*a^3*a^1*b^3*b^3}

Now simplify. Any terms with an exponent of 3 will be moved out of the radical (rule #2):

2\sqrt[3]{3*a^3*a^3*a^3*a^1*b^3*b^3}\\\\\\2*a*a*a\sqrt[3]{3*a^1*b^3*b^3}\\\\\\2*a*a*a*b*b\sqrt[3]{3*a^1}

Simplify:

2a^3b^2\sqrt[3]{3a}

:Done

6 0
3 years ago
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