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alexira [117]
3 years ago
9

Luis rides his bicycle 3/4 mile in 15 minutes, or 1/4 hour, along the bike trail. Assuming he rides at a constant rate, what is

his speed, in miles per hour?
Mathematics
2 answers:
Oksi-84 [34.3K]3 years ago
7 0
The answer would be 3mph because 3/4 / 1/4 = 3. So the answer would be 3mph.
photoshop1234 [79]3 years ago
6 0

Answer:

His speed in miles per hour is:

<u>3Mph</u>

Step-by-step explanation:

Depending on the speed you take in miles per minute when passing it to miles per hour, you should consider the time it takes you to travel a mile.

Now: If 3/4 of a mile is 0.75 miles.

And it takes 15 minutes, so how long does it take 1 mile?

It is a rule of three.

0.75 miles = 15 minutes

1 mile = X

Clearing X would give :

 X = 15 * 1 / 0.75

X = 20 minutes takes a mile to travel

Now if it goes to 1Mpm how much is in Mph?

If it takes 20 minutes to travel 1 mile, how many travels in 60 minutes (1 hour)

Again rule of 3.

20 minutes = 1 mile

60 minutes = X

Clearing X would give:

X = 60/20

<u>X = 3 miles per hour.</u>

<u>Luis rides 3 miles per hour.</u>

You might be interested in
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
1 year ago
Please help me ASAP!
FinnZ [79.3K]

A. d=50t B. 50,100,150,200,250 C. 50 days

5 0
3 years ago
Can someone please help me?
Crazy boy [7]

Answer:

70°

Step-by-step explanation:

since two lengths are equal to 3.5 that’s means there’s are two equal angles (55° and 55°)

a triangle adds up to 180°

so to find x we set this up:

x +55 +55 = 180

x + 110 = 180

x = 70°

3 0
3 years ago
Will give you brilliantest
Zina [86]
I don’t know but maybe 2
6 0
1 year ago
What is the difference between the two graphs at X = -3
schepotkina [342]

Answer:

5

Step-by-step explanation:

Blue: when x = - 3, y = 5

Green: when x = -3, y = 0

The difference between the two graphs at X = -3 : 5 - 0 = 5

Answer

5

6 0
3 years ago
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