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Ad libitum [116K]
3 years ago
11

X + 2Y → XY2

Physics
1 answer:
Nikolay [14]3 years ago
3 0

Answer:

                         \large\boxed{\large\boxed{OptioncC)15.0mol}}

Explanation:

The reaction between hypothetical elements X and Y to produce hypothetical compound XY₂ is represented with the chemical equation:

  • X + 2Y → XY₂

That equation means that one atom (or one mole of atoms) of element X reacts with 2 atoms (or two moles of atoms) of element Y to produce one molecule (one mole of molecules) of compound XY₂.

Elements X and Y are the reactants, and compound XY₂ is the product.

Hence, the mole ratio is:

  • 1 mol X : 2 mol Y : 1 mol XY₂

Since, 10.0 mol of Y completely react you can set the corresponding proportions with X and XY₂ to find how many moles of them will be in the reaction:

<u>1. Moles of X</u>:

  • Theoretical ratio: 1 mol of X / 2 mol of Y

  • Ratio with 10.0 mol of Y: U / 10.0 mol of Y

  • Proportion: equal the two ratios: 1 mol X / 2 mol Y = U / 10.0 mol Y

  • Solve for U: U = 10.0 mol Y × 1 mol X / 2 mol Y = 5.0 mol X

  • Result: 5.0 moles of X are in the reaction.

<u>2. Total moles of X and Y in the reaction:</u>

  • The total number of moles is the sum of the moles of the two reactants: 10.0 moles of Y + 5.0 moles of X = 15.0 moles. Hence 15.0 mol of X and Y are in the reaction: option C).

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CAN YOU HELP, JUST NUMBER 3​
bonufazy [111]

Answer:

its b option balance hi your last question

6 0
3 years ago
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An unwary football player collides with a padded goalpost while running at a velocity of 7.50 m/s and comes to a full stop after
frez [133]

Answer:

(a) the deceleration of the player is -80.36 m/s²

(b) the time the collision last is 0.093 s

Explanation:

Given;

Initial velocity of the football player, u = 7.50 m/s

Final velocity of the football player, v = 0

distance traveled = compression of the pad, s = 0.35 m

Part (a) the deceleration of the player

v² = u² + 2as

0 = 7.5² + (2 x 0.35)a

0 = 56.25 + 0.7a

- 56.25 = 0.7a

a = -56.25 / 0.7

a = -80.36 m/s²

Part (b) the time the collision last

v = u + at

t = (v - u)/a

t = (0 - 7.5)/ -80.36

t = - 7.5 / -80.36

t = 0.093 s

7 0
3 years ago
The water is flowing through the horizontal constricted pipe. The pressure at one end is 4500Pa, speed is 3m/s and area of cross
Oksana_A [137]

The speed and pressure at another end will be 9 m/sec and -31500 pascals.

<h3>What is gauge pressure?</h3>

The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.

Given data in problem is;

For horizontal pipe, Z₁=Z₂

Pressure at end 1, P₁ = 4500Pa

Speed at end 1, V₁ = 3 m/sec

Speed at end 2, V₂ = ? m/sec

Area of cross-section at end 1,A₁ =A

Area of cross-section at end 1,A₂ = A/3

From the continuity equation;

A₁V₁=A₂V₂

A× 3  = (A/3)×V₂

V₂ = 9 m/sec

From Bernoulli's equation;

\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2  \\\\ \frac{P_1-P_2}{\rho g } = \frac{v_2^2-v_1^2}{2g} \\\\ \frac{P_1-P_2}{\rho} =  \frac{v_2^2-v_1^2}{2} \\\\ \frac{4500-P_2}{1000} =  \frac{9^2-3^2}{2} \\\\ 4500 -P_2 = 36000 \\\\ P_2 =  - \ 31,500 \ pa

Hence the speed and pressure at another end will be 9 m/sec and -31500 pascals.

To learn more about the gauge pressure, refer to the link;

brainly.com/question/14012416

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7 0
2 years ago
Hi im really confused:
Vitek1552 [10]

The energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

U =  c_{p} m ΔT

U = Energy

c_{p} = Specific heat

m = Mass

ΔT = Change in temperature

ρ = Density

V = Volume

ρ = 1000 g / m³ (Dry air )

c_{p} = 1 J / g K

ΔT = 5 °C

V = 4 * 4 * 3

V = 48 m³

m = ρ V

m = 1000 * 48

m = 48000 g

U = 1 * 48000 * 7

U = 336000 J

U = 336 kJ

Therefore, the energy required to raise the temperature of the air in a room by 5.0°C is 336 kJ

To know more about energy required to raise temperature

brainly.com/question/12372041

#SPJ1

3 0
1 year ago
In which situation can you be at rest and moving at the same time
sineoko [7]

Answer:Being at rest is a relative term. Relative to earth we are at rest when we are sitting down. However, you are moving because the earth is moving its orbit around the sun.

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