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padilas [110]
3 years ago
11

A teacher pushes on a wall with a force of 125N but the wall does not move. Calculate the amount of work in Joules the teacher a

ccomplished.
Physics
2 answers:
nata0808 [166]3 years ago
8 0

Answer:

The answer would be 0

Explanation:

The Formula for work is force multiplied by distance

W=F*D

The force is 125N times the distance and becase the teacher didnt move it would be 0, 125*0 = 0 so the answer is 0Joules

Annette [7]3 years ago
7 0

Answer:

0

Explanation:

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A stone is dropped into a river from a bridge at a height h above the water. Another stone is thrown vertically down at a time t
Mumz [18]

Answer:

v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

Explanation:

We will apply the equations of kinematics to both stones separately.

First stone:

Let us denote the time spent after the second stone is thrown as 'T'.

y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t

Second stone:

y - y_0 = v_{y_0}T + \frac{1}{2}aT^2\\0 - h = v_{y_0}T -\frac{1}{2}gT^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\sqrt{\frac{2h}{g}} - t)^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\frac{2h}{g} + t^2 - 2t\sqrt{\frac{2h}{g}})\\-h = v_{y_0}\sqrt{\frac{2h}{g}} - v_{y_0}t - h -\frac{g}{2}t^2 + gt\sqrt{\frac{2h}{g}}\\v_{y_0}(\sqrt{\frac{2h}{g}} - t) = \frac{g}{2}t^2 - gt\sqrt{\frac{2h}{g}}\\v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

6 0
3 years ago
Read 2 more answers
In Space, an astronaut releases a wrench from his hand. The wrench has a mass of 4 grams and is traveling with a velocity of -15
Vladimir [108]

Answer:

v_2=8.85\times 10^{-4}\ m/s

Explanation:

We have,

Mass of a wrench, m₁ = 4 g = 0.004 kg

Speed of wrench, v₁ = -15 m/s

Mass of the Astronaut, m₂ = 70 kg

It is required to find Astronaut's velocity. Let it is v₂. Using the conservation of linear momentum to find it.

m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\=\dfrac{0.004\times (-15)}{70}\\\\=-8.85\times 10^{-4}\ m/s

So, his velocity is 8.85\times 10^{-4}\ m/s.

8 0
3 years ago
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3 years ago
A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the stone's ti
Oksana_A [137]

Complete Question

A baseball is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stop watch measures the ball's time in the air until it hits the ground to be 4.3 s. How far does the baseball travel horizontally?

Answer:

The distance covered horizontally is  d =  43 \ m

Explanation:

From the question we are told that

     The initial horizontal velocity is  u = 10 \ m/s

     The time taken by the ball in the air is  t = 4.3 \ s

Generally the distance traveled by the ball is  

       d =  u  *  t

=>     d =   10 * 4.3

=>     d =  43 \ m

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3 years ago
A train moves at a constant velocity of 50km/h. How far will it move in 0.5 h?
Semenov [28]
Distance = velocity
time distance = 50 km/h x .5 hour distance so your answer would be 25km
5 0
4 years ago
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