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Lelu [443]
3 years ago
8

John walks 1.00 km north, then turns right and walks 1.00 km east. His speed is 1.50 m/s during the entire stroll.a) What is the

magnitude of his displacement, from beginning to end?b) If Jane starts at the same time and place as John, but walks in a straight line to the endpoint of John's stroll, at what speed should she walk to arrive at the endpoint just when John does?
Physics
1 answer:
avanturin [10]3 years ago
3 0

Answer:

(a) 1.414 km

(b) 1.06 m/s

Explanation:

(a) For John:

Distance = 1 km north and then 1 km east

Speed = 1.5 m/s

total distance traveled = 1 + 1 = 2 km = 2000 m

Time taken to travel = Distance / speed

t = 2000 / 1.5 = 1333.3 seconds

Displacement = \sqrt{1^{2}+1^{2}}=1.414 km

(b) For jane :

Time is same as john = 1333.33 second

Distance = 1.414 km = 1414 m

Speed = distance / time = 1414 / 1333.33 = 1.06 m/s

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Shawn and his bike have a total mass of
Trava [24]

Answer:

Shawn's kinetic energy is 61.45 J.

Explanation:

Given;

Mass of the system is, m=52.3\ kg

Displacement of the bike is, d=1.6\ km=1.6\times 1000=1600\ m

Time taken is, t=17.4\ min=17.4\times 60=1044\ s

Let the constant velocity be v.

For constant velocity, magnitude of velocity is given as distance by time.

Therefore, v=\frac{d}{t}=\frac{1600}{1044}=1.533\ m/s

Now, kinetic energy of a body is given as:

KE=\frac{1}{2}mv^2

Here, m=52.3\ kg,\ v=1.533\ m/s

\therefore KE=\frac{1}{2}\times 52.3\times (1.533)^2\\KE=0.5\times 52.3\times 2.35\\KE=61.45\ J

Therefore, Shawn's kinetic energy is 61.45 J.

3 0
3 years ago
A stone of mass 150g is rotated in a horizontal circle at 10m/s which is attached to the end of a 1m long. what will be the acce
erastova [34]

force is mass multiply by acceleration so it will be 150 multiply by 10 is 1500N

8 0
2 years ago
Read 2 more answers
A 45.00 kg person in a 43.00 kg cart is coasting with a speed of 19 m/s before it goes up a hill. there is no friction, what is
HACTEHA [7]

Answer:

the maximum vertical height the person in the cart can reach is 18.42 m

Explanation:

Given;

mass of the person in cart, m₁ = 45 kg

mass of the cart, m₂ = 43 kg

acceleration due to gravity, g = 9.8 m/s²

final speed of the cart before it goes up the hill, v = 19 m/s

Apply the principle of conservation of energy;

mgh_{max} = \frac{1}{2}mv^2_{max}\\\\ gh_{max} = \frac{1}{2}v^2_{max}\\\\h_{max} = \frac{v^2_{max}}{2g} \\\\h_{max} =\frac{(19)^2}{2\times 9.8} \\\\h_{max} = 18.42 \ m

Therefore, the maximum vertical height the person in the cart can reach is 18.42 m

5 0
3 years ago
A pulley system has an efficiency of 74.2%. If you perform 200 J of work, how
Fudgin [204]

Answer:

C

Explanation:

If a pulley system has an efficiency of 74.2%, then only that fraction of the work performed will be useful. 74.2%=0.742. 0.742*200 is about 148J. Hope this helps!

8 0
3 years ago
An 80-kgkg quarterback jumps straight up in the air right before throwing a 0.43-kgkg football horizontally at 15 m/sm/s . How f
vladimir1956 [14]

Answer:

V = 0.0806 m/s

Explanation:

given data

mass quarterback = 80 kg

mass football = 0.43 kg

velocity = 15 m/s

solution

we consider here momentum conservation is in horizontal direction.

so that here no initial momentum of the quarterback

so that final momentum of the system will be 0

so we can say

M(quarterback) ×  V = m(football) × v (football)   ........................1

put here value we get

80 ×  V  = 0.43  × 15

V = 0.0806 m/s

5 0
3 years ago
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