Question

79. If the takeoff velocity of an airplane on a runway is 300 km/hr with an acceleration of 2 m/s. What is the takeoff time

Answer 1

Answer:

The take off time is equal to 41.66s.

Explanation:

Given that,

The initial speed of the airplane, u = 0

Acceleration, a = 2 m/s²

Let v is the take off time. Using first equation of motion,

v = u +at

Put v = 300 km/hr = 83.3 m/s

So,

$t=\dfrac{v}{a}\\\\t=\dfrac{83.33}{2}\\\\t=41.66\ s$

So, the take off time is equal to 41.66s.