<span>Hydrogen ion, strictly, the nucleus of a hydrogen atom separated from its accompanying electron. Thehydrogen nucleus is made up of a particle carrying a unit positive electric charge, called a proton. The isolated hydrogen ion, represented by the symbol H +, is therefore customarily used to represent aproton.</span><span>
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Answer:
252.5g
Explanation:
Given parameters:
Volume of vodka = 0.8L
Molarity of ethanol = 6.86M
Unknown:
Mass of ethanol = ?
Solution:
Molarity is one of the ways of expressing concentration. It is the number of moles of a substance in a solution.
Since Vodka = ethanol + water = solution
Molarity = 
Number of moles of ethanol = molarity of vodka x volume of solution
Once we obtain the number of moles, we can derive the mass of the ethanol;
Number of moles = 6.86M x 0.8L = 5.49moles
Mass of ethanol = number of moles x molar mass
molar mass of ethanol = 12 + 3(1) + 12 + 2(1) + 16 + 1 = 46g/mol
Mass of ethanol = 5.49 x 46 = 252.5g
Answer:
4204 K
Explanation:
Step 1: Data
<em>Given data</em>
- Density of uranium hexafluoride (ρ): 0.5820 g/L
- Pressure of uranium hexafluoride (P): 0.5073 atm
<em>Required data</em>
- Universal gas constant (R): 0.08206 atm.L/mol.K
- Molar mass of uranium hexafluoride (M): 352.02 g/mol
Step 2: Calculate the temperature of the gas
We will use the following expression derived from the ideal gas equation.
P × M = ρ × R × T
T = P × M/ρ × R
T = 0.5073 atm × (352.02 g/mol)/(0.5820 g/L) × (0.08206 atm.L/mol.K)
T = 4204 K
Answer:
1.40 moles.
Explanation:
The balanced chemical equation for the reaction of Phosphorus and Oxygen is as follows -

In Part A, the oxygen was taken in excess. So Phosphorus will be the limiting reagent.
Since, 2 moles of
is formed by 4 moles of 
So, for 1.8 moles of
amount of required moles of
=
In Part B, the phosphorus was taken in excess so oxygen will be the limiting reagent.
Since, 2 moles of
is formed by 5 moles of oxygen
So, for 1.40 moles of
moles of
required = 
Thus as of now we have 3.60 moles of
and 3.50 moles of
.
As in the reaction of formation of
, oxygen is the limiting reagent.
So the moles of
formed by the 3.50 moles of oxygen will be
=
= 1.40 moles.
What do you mean.....kelvin?