2 answers:
T(s(x)) = -5
Substitute the value in for x and evaluate = -2
T(s(2))
=s(x)=2x-1
=s(2)=2(2)-1
=s
(2)=4-1
=s(2)=3
s(2)=3
t(s(2))=-2x^2+2
t(3)=-2(3)2+2
t(3)=-2(9)+2
t(3)=-18+2
t(3)=-16
Therefore the value of t(s(2)) is -16
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