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Drupady [299]
4 years ago
5

The mean of a set of eight numbers is 8 and the mean of a different set of twelve numbers is m. Given that the mean if the combi

ned set of twenty numbers is 5, calculate m.
Mathematics
1 answer:
Basile [38]4 years ago
8 0
Mean=total/the number of values =>total=mean*the number of values
the total of the first set of 8 numbers is : total=8*8=64
the total of the second set of 12 numbers is: 12m
the total of the 20 numbers is: 64+12m
the mean of the 20 number is: (64+12m)/20=5
solve for m: 64+12m=100
12m=36
m=3
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5 0
3 years ago
Help help help help
Alex

Answer:

<h3>b=\frac{t-5}{4}</h3>

Step-by-step explanation:

4b+5=t

First, you must get the variable alone! Substract 5 from both sides!

4b<u>+5=t </u>

    -5  -5

The 5 cancels out because 5-5=0

The new equation is 4b=t-5

You must divide by 4 to get the variable alone since your solving for b!

<u>4b=t-5</u>

4      4

b= \frac{t-5}{4} \\

This is your answer!

5 0
3 years ago
Can somebody help me please?
madreJ [45]
Factor
(x+7)(x-2)

Proof
7-2=5
7*-2=-14

Zeros
x+7=0
x=-7

x-2=0
x=2

Final answer: C

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