A. =4^(-11/3)*4^(2/3)
=4^(-9/3)
=4^(-3)
=1/64
Answer: The mean and standard deviation are 567.2 and 89.88 resp.
Step-by-step explanation:
Since we have given that
For 370 parts per million = 7% = 0.07
For 440 parts per million = 10% = 0.10
For 550 parts per million = 49% = 0.49
For 670 parts per million = 34% = 0.34
So, Mean of the carbon dioxide atmosphere for these trees would be
![E[x]=370\times 0.07+440\times 0.1+550\times 0.49+670\times 0.34=567.2](https://tex.z-dn.net/?f=E%5Bx%5D%3D370%5Ctimes%200.07%2B440%5Ctimes%200.1%2B550%5Ctimes%200.49%2B670%5Ctimes%200.34%3D567.2)
And
![E[x^2]=370^2\times 0.07+440^2\times 0.1+550^2\times 0.49+670^2\times 0.34=329794](https://tex.z-dn.net/?f=E%5Bx%5E2%5D%3D370%5E2%5Ctimes%200.07%2B440%5E2%5Ctimes%200.1%2B550%5E2%5Ctimes%200.49%2B670%5E2%5Ctimes%200.34%3D329794)
So, Variance would be
![Var\ x=E[x^2]-E[x]^2=329794-567.2^2=8078.16](https://tex.z-dn.net/?f=Var%5C%20x%3DE%5Bx%5E2%5D-E%5Bx%5D%5E2%3D329794-567.2%5E2%3D8078.16)
So, the standard deviation would be

Hence, the mean and standard deviation are 567.2 and 89.88 resp.
Answer:
$4,309.12
Step-by-step explanation:
The computation of the interest earned is given below:
But before that the amount would be
Amount = Principal × (1 + rate of interest)^number of years
= $6,000 × (1 + 0.07)^8
= $6,000 × 1.07^8
= $10,309.12
Now the interest earned is
= Amount - principal
= $10,309.12 - $6,000
= $4,309.12
A total of 440 students took part in the survey. Each student makes up 0.8181818182% of the central angle of the circle graph. You get to this number by dividing 360 degrees by 440 students. Then you simply multiply this number by 110 students (who liked the program).
0.8181818182%*110=90 degrees
Answer:
m∠SVT = 79*
Step-by-step explanation:
8y - 33 = 5y + 9
8y = 5y + 42
3y = 42
y = 14
_____
5y + 9
5(14) + 9
70 + 9
79