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deff fn [24]
3 years ago
8

Simplify each expression 1/3^-3

Mathematics
2 answers:
pishuonlain [190]3 years ago
5 0

Answer:

3^{+1}

Step-by-step explanation:

<u>https://www.symbolab.com/solver/equation-calculator/1%2F3%5E%7B-%7D3</u>

go to the link and it shows it step by step...

xxTIMURxx [149]3 years ago
3 0

Answer:

27

Step-by-step explanation:

Use exponent laws

1/3^-3 = 3^3 = 27

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Find the domain of the Bessel function of order 0 defined by [infinity]J0(x) = Σ (−1)^nx^2n/ 2^2n(n!)^2 n = 0
Snowcat [4.5K]

Answer:

Following are the given series for all x:

Step-by-step explanation:

Given equation:

\bold{J_0(x)=\sum_{n=0}^{\infty}\frac{((-1)^{n}(x^{2n}))}{(2^{2n})(n!)^2}}\\

Let   the value a so, the value of a_n  and the value of a_(n+1)is:

\to  a_n=\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}

\to a_{(n+1)}=\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}

To calculates its series we divide the above value:

\left | \frac{a_(n+1)}{a_n}\right |= \frac{\frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2}}{\frac{(-1)^2n x^{2n}}{2^{2n}(n!)^2}}\\\\

           = \left | \frac{(-1)^{n+1} x^{2(n+1)}}{2^{2(n+1)}((n+1))!^2} \cdot \frac {2^{2n}(n!)^2}{(-1)^2n x^{2n}} \right |

           = \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)!^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |

           = \left | \frac{ x^{2n+2}}{2^{2n+2}(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\= \left | \frac{x^{2n}\cdot x^2}{2^{2n} \cdot 2^2(n+1)^2 (n!)^2} \cdot \frac {2^{2n}(n!)^2}{x^{2n}} \right |\\\\

           = \frac{x^2}{2^2(n+1)^2}\longrightarrow 0   for all x

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8 0
4 years ago
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Answer:

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Step-by-step explanation:

5 0
3 years ago
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Can someone please help me!?!
poizon [28]

Answer:

-25 and -4

Step-by-step explanation:

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3 0
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11111nata11111 [884]

Answer:

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Step-by-step explanation:

in the word 'MATHEATICS' has no line symmetry.

8 0
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solmaris [256]
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Because the sum of adjacent angles on a straight line is 180⁰ (not 360⁰), the statement is false.

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3 years ago
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