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juin [17]
3 years ago
15

Click to see all PLS HELP I KNOW ITS LATE HURRY!​

Mathematics
1 answer:
fiasKO [112]3 years ago
6 0

Answer: 9.5/10 mile long

Step-by-step explanation:

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day 1= 325 cans

day 2-9 = 944 (118 cans each day)...

118*8 = 944

therefore total number of cans =

day 1 + days 2-9

= 325+944

=1269

4 0
3 years ago
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4 years ago
Look back at the plans these students used to solve the word problem below.
yanalaym [24]
The answer should be option A.
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3 years ago
Polygons QRST and Q’R’S’T’ are shown on the coordinate grid: A coordinate plane with two polygons is shown. Polygon QRST has ver
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Answer:

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Step-by-step explanation:

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4 0
4 years ago
If you choose two cards at random from a deck of 52 cards, what is the probability that it is two diamonds?
kari74 [83]
<h3>Answer:</h3>

1/17 or 0.0588 (without replacement)

<h3>Step-by-step explanation:</h3>

To answer this question we need to know the following about a deck of cards

  • A deck of cards contains 4 of each card (4 Aces, 4 Kings, 4 Queens, etc.)
  • Also there are 4 suits (Clubs, Hearts, Diamonds, and Spades).
  • Additionally, there are 13 cards  in each suit (Clubs/Spades are black, Hearts/Diamonds are red) .

In this case, we are required to determine the probability of choosing two diamonds.

  • There are 13 diamonds in the deck.
  • Assuming, the cards were chosen without replacement;

P(Both cards are diamonds) = P(first card is diamond) × P(second card is diamond)

P(First card is diamond) = 13/52

If there was no replacement, then after picking the first diamond card, there are 12 diamond cards remaining and a total of 51 cards remaining in the deck.

Therefore;

P(Second card is diamond) = 12/51

Thus;

P(Both cards are diamonds) = 13/52 × 12/51

                                               = 156/2652

                                              = 1/17 or 0.0588

Hence, the probability of choosing two diamonds at random (without replacement) is 1/17 or 0.0588.

5 0
4 years ago
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