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3 years ago

In the figure, what is the value of x? a. 45 b. 60 c. 75 d. 90

Mathematics

1 answer:

Katarina [22]3 years ago

5 0

<h3>Answer: x = 90</h3>

============================================

Explanation:

The arc measure is some unknown number x, so is the angle formed by the tangents that form based on this arc. The arc and angle add to 180, so,

x+x = 180

2x = 180

2x/2 = 180/2

x = 90

A right angle forms if we were to draw segments from the center of the circle to the points of tangency. We have a square forming if we do so. Recall that the points of tangency have the radius and tangent segments meet up at a 90 degree angle.

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Mrs. Williamson had 18 students in her homeroom at the beginning of the school year and 24 students at the end of the year. What

jarptica [38.1K]

Answer:

25%

Step-by-step explanation:

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2 years ago

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

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3 years ago

Mrs.gauthier plans to take her class on 2 field trips this year there are 23 students in her class and each field trip will cost

Alina [70]

If there is 2 field trips with 23 students and each student costs $5 dollars. So for the 1st trip it will be 23x$5

1st trip- $115

And on the second trip its the same because there is 23 students that cost 5 dollars so it will be 23x5

2nd trip- $115

To find out the total of both trips youd add 115+115/

In total, for both trips it will cost $230 dollars.

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3 years ago