Answer:
P_min = 490 N/m²
P_max = 7350 N/m²
Explanation:
Formula for pressure is;
Pressure = Force/Area
We are given;
Mass = 30 kg
Dimensions of Block = 0.1 m by
0.4 m by 1.5 m.
Force(weight) = mg = 30 × 9.8 = 294 N
For minimum pressure, it will be at maximum area.
Max area will be at biggest dimensions.
Max area = 0.4 × 1.5 = 0.6 m²
P_min = 294/0.6
P_min = 490 N/m²
Similarly, maximum pressure will be at minimum area.
Minimum area = 0.1 × 0.4 = 0.04 m²
P_max = 294/0.04
P_max = 7350 N/m²
If spring constant is doubled, the mass on spring will be doubled as well. according to this formula, F=ke
k stands for spring constant and e stands for the length extended
A.how much power is needed to push the box at a speed of.
Answer:
Attracted I believe.
Explanation:
A plastic rod is an insulator if rubbed by say a dish cloth and the "free" electrons from the plastic rod transfer to the cloth then the rod becomes positively charged because of the loss if it's electrons upsetting the balance of positive/negative charge The cloth receiving the electrons becomes negatively charged.
Positive and negative charges attract like when you rub a balloon on your hair and it sticks. Although they both were originally neutral "having the same positive and negative"
the balloon loses some of it's electrons becoming positive whilst your hair becomes negative although they just transferred from each other the two will still attract one another now that their is an unbalance.
Answer:
The velocity of the ball before it hits the ground = 21.4m/s
Explanation:
The question can be solved as a projectile problem. One of the main characteristics of the parabolic motion is the symmetry it has as long as the initial height is equal to the final height with respect to a reference system, the vertical displacement of the horizontal displacement being independent.
The vertical component of velocity is 13m/s
The horizontal component is 17m/s
The ball's pathway is defined by a right angle triangle .
Using Pythagorean
Let vertical component be a
Let horizontal component be b
Let the speed of the ball before hitting the ground be c
Pythagorean is given by:
a^2 + b^2 = c^2
13^2 + 17^2 = c^2
169 + 289 = c^2
458 = c^2
Sqrt(458) = c
21.4 m/s = c