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3 years ago

What percentage of energy can be transformed when an energy transformation from potential to kinetic occurs?

Physics

1 answer:

GREYUIT [131]3 years ago

7 0

Answer:

100%

Explanation:

i did the same question

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A car sitting at a red light begins to accelerate at 2.0 m/s2 when the light turns green. It continues with this acceleration un

KonstantinChe [14]

Answer:

$d = 820 m$

Explanation:

here we know that car starts from rest and continue to accelerate till it will reach to maximum speed of 20 m/s

so we will have

$v_f - v_i = at$

$20 - 0 = 2t$

$t = 10 s$

so car will accelerate till t = 10 then it will move with uniform speed

so the distance moved by the car till it accelerates is given as

$d = \frac{1}{2}at^2$

$d = \frac{1}{2}(2)(10^2)$

$d_1 = 100 m$

now it will move with uniform speed for next 36 s

so we have

$d_2 = 20(36) = 720 m$

so total distance moved by the car is given as

$d = d_1 + d_2$

$d = 100 + 720$

$d = 820 m$

8 0

3 years ago

Question 1:

german

Answer:

well I done really know ask the others person

7 0

3 years ago

One of the characteristics of the planet mars that makes it very different from earth is that it does not have a large magnetic

Ket [755]

Answer:

It is most likely solid.

Explanation:

8 0

3 years ago

Read 2 more answers

Sound level B in decibels is defined as

Lelechka [254]

Answer:

The approximate combined sound intensity is $I_{T}=1.1\times10^{-4}W/m^{2}$

Explanation:

The decibel scale intensity for busy traffic is 80 dB. so intensity will be

$10log(\frac{I_{1}}{I_{0}} )=80$ , therefore $I_{1}=1\times10^{8}I_{0}=1\times10^{8} * 1\times10^{-12}W/m^{2}=1\times10^{-4}W/m^{2}$

In the same way for the loud conversation having a decibel intensity of 70 dB.

$10log(\frac{I_{2}}{I_{0}} )=70$ , therefore $I_{2}=1\times10^{7}I_{0}=1\times10^{7} * 1\times10^{-12}W/m^{2}=1\times10^{-5}W/m^{2}$

Finally we add both of them $I_{T}=I_{1}+I_{2}=1\times10^{-4}W/m^{2}+1\times10^{-5}W/m^{2}=1.1\times10^{-4}W/m^{2}$ , is the approximate combined sound intensity.

3 0

3 years ago

A big lump of meat of mass 5Kg is hung from a spring balance in an elevator. Find the reading of the balance of (I) the elevator

Mrrafil [7]

The reading of the balance if ,

I ) If the elevator is moving with a steady speed = 50 N

II ) If the elevator is moving upwards with acceleration of 0.2 m / s² = 51 N

T = m g + m a

T = Force

m = Mass

g = Acceleration due to gravity

a = Acceleration

m = 5 kg

g = 10 m / s²

I ) If the elevator is moving with a steady speed,

At steady speed, a = 0

T = ( 5 * 10 ) + ( 5 * 0 )

T = 50 N

II ) If the elevator is moving upwards with acceleration of 0.2 m / s²,

a = 0.2 m / s²

T = ( 5 * 10 ) + ( 5 * 0.2 )

T = 50 + 1

T = 51 N

Therefore, the reading of the balance if ,

I ) If the elevator is moving with a steady speed = 50 N

II ) If the elevator is moving upwards with acceleration of 0.2 m / s² = 51 N

To know more about reading on a spring balance

brainly.com/question/14819147

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7 0

1 year ago