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Gwar [14]
3 years ago
6

Haileys comet is a comet that passes close to earth every 75 years. based on this passage, which gravitational attraction has th

e most influence on the movement of this astronomical object
Physics
2 answers:
Strike441 [17]3 years ago
8 0
The answers to this question is gravity that what I would pick
yawa3891 [41]3 years ago
7 0

Answer:

gravity lol

Explanation:

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In 40 words or fewer, summarize the connection between kinetic and thermal energy.<br> PLEASE REPLY
xz_007 [3.2K]

Answer:

Explanation:

kenetic is made for thermal things

8 0
3 years ago
How long does a lunar eclipse last? A)seconds B)Minutes C)Days D) Weeks
bonufazy [111]
Well, it happens a few weeks ahead, then for a total of 3 hours and 40 minutes.
3 0
3 years ago
An electric wall clock has a second hand 15 cm long. at the tip of his hand, what is the magnitude of the velocity?
Mila [183]

The velocity of the tip of the second hand is 0.0158 m/s

Explanation:

First of all, we need to calculate the angular velocity of the second hand.

We know that the second hand completes one full circle in

T = 60 seconds

Therefore, its angular velocity is:

\omega = \frac{2\pi}{T}=\frac{2\pi}{(60)}=0.105 rad/s

Now we can calculate the velocity of a point on the tip of the hand by using the formula

v=\omega r

where

\omega=0.105 rad/s is the angular velocity

r = 15 cm = 0.15 m is the radius of the circle (the distance of the point from the centre of rotation)

Substituting,

v=(0.105)(0.15)=0.0158 m/s

Learn more about angular motion here:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

#LearnwithBrainly

7 0
3 years ago
Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 23.5 m above water wit
Elodia [21]

As stated in the statement, we will apply energy conservation to solve this problem.

From this concept we know that the kinetic energy gained is equivalent to the potential energy lost and vice versa. Mathematically said equilibrium can be expressed as

\Delta KE = \Delta PE

\frac{1}{2}mv_f^2-\frac{1}{2} mv_0^2 = mgh_2-mgh_1

Where,

m = mass

v_{f,i} = initial and final velocity

g = Gravity

h = height

As the mass is tHe same and the final height is zero we have that the expression is now:

\frac{1}{2}v_f^2-\frac{1}{2} v_0^2 = gh_2

\frac{1}{2} (v_f^2-v_0^2) = gh_2

(v_f^2-v_0^2) = 2gh_2

v_f = \sqrt{2gh_2+v_0^2}

v_f = \sqrt{2(9.8)(23.5)+13.6^2}

v_f = 25.4m/s

7 0
3 years ago
A 2 kg ball is thrown upward with a velocity of 15 m/s. What is the kinetic energy of the ball as it is being thrown?
marusya05 [52]
KE=1/2 m v^2
KE= .5 x 2kg x 15m/s to the 2nd power
KE=225 km/s
7 0
3 years ago
Read 2 more answers
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