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4 years ago

6

Haileys comet is a comet that passes close to earth every 75 years. based on this passage, which gravitational attraction has th

e most influence on the movement of this astronomical object

2 answers:

Strike441 [17]4 years ago

8 0

The answers to this question is gravity that what I would pick

yawa3891 [41]4 years ago

7 0

Answer:

gravity lol

Explanation:

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The wattage marked on a lightbulb is not an inherent property of the bulb but depends on the voltage to which it is connected, u

Mashutka [201]

Answer:

The current that flows through the lamp is 0.5 A.

Explanation:

A lamp functions like a resistor and the real power absorbed by a resistor is given by the product of the voltage drop across it's terminals and the current that flows through it. If we wish to find the current that this lamp draws we should divide the wattage given (60 W) by the voltage drop provided (120 V). We then have:

i = P/V = 60/120 = 0.5 A.

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3 years ago

At which point does the planet have the least gravitational force acting on it?

Elza [17]

Answer:

At which point does the planet have the least gravitational force acting on it?

Explanation:

In an elliptical orbit, when a planet is at its furthest point from the Sun, it is under the least amount of gravity, meaning that the force of gravity is strongest when it is closest.

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3 years ago

Read 2 more answers

The actual depth of a shallow pool 1.00 m deep is not the same as the apparent depth seen when you look straight down at the poo

DedPeter [7]

Answer:

d' = 75.1 cm

Explanation:

It is given that,

The actual depth of a shallow pool is, d = 1 m

We need to find the apparent depth of the water in the pool. Let it is equal to d'.

We know that the refractive index is also defined as the ratio of real depth to the apparent depth. Let the refractive index of water is 1.33. So,

$n=\dfrac{d}{d'}\\\\d'=\dfrac{d}{n}\\\\d'=\dfrac{1\ m}{1.33}\\\\d'=0.751\ m$

or

d' = 75.1 cm

So, the apparent depth is 75.1 cm.

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3 years ago

A nonconducting ring with a radius of 11.5 cm is uniformly charged with a total positive charge of 10.0 µC. The ring rotates at

zhuklara [117]

Answer:

$B=1.21*10^{-10}T$

Explanation:

The magnitude of the magnetic field on the axis of the ring is given by:

$B=\frac{\mu_0 IR^2}{2(r^2+R^2)^{\frac{3}{2}}}(1)$

$\mu_0$ is the permeability of free space, $I$ is the flowing current through the ring, $R$ is the ring's radius and $r$ is the distance to the center of the ring.

The flowing current through the ring is defined as the ring's charge divided into the time taken by the charge to complete one revolution, that is, the period $T=\frac{2\pi}{\omega}$ . So, we have:

$I=\frac{q}{T}\\I=\frac{q}{\frac{2\pi}{\omega}}\\\\I=\frac{\omega q}{2\pi}\\I=\frac{18\frac{rad}{s}(10*10^{-6}C)}{2\pi}\\I=2.87*10^{-5}A$

Now, replacing in (1):

$B=\frac{(4\pi*10^{-7}\frac{T\cdot m}{A})(2.87*10^{-5}A)(0.115m)^2}{2((0.05m)^2+(0.115m)^2)^{\frac{3}{2}}}\\B=1.21*10^{-10}T$

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4 years ago

1. What conditions must be met for information to be considered true science?

olga55 [171]

Scientific law are proven scientific fact a theory isn’t it could be if you provide details of how it is a fact with investigations and observations,data and etc

3 0

3 years ago