Answer:
k = 1,250 N/m
Explanation:
Use the formula F=kx, with F=5N and x=0.04m
Then the spring constant (k) is 5/0.04
The change in the angle of circular motion is analogous to <u>linear velocity</u> in linear motion
<u>Explanation:</u>
We define angular velocity ω as the rate of change of an angle. The greater the rotation angle in a given amount of time, the greater the angular velocity. angular velocity refers to how fast an object rotates or revolves relative to another point, i.e. how fast the angular position or orientation of an object changes with time.
The units for angular velocity are radians per second (rad/s). Angular velocity ω is analogous to linear velocity v. Linear velocity is the measure of “the rate of change of displacement with respect to time when the object moves along a straight path.” It is a vector quantity.
The ease with which a material allows electricity to move is called
C. CONDUCTIVITY
Answer:
the diameter of the second pipe is 2.52 in
Explanation:
Given the data in the question;
We know that; the rate of flow is the same;
so
Av1 = Av2
v ∝ √h
= 
= √( 
)
( π/4.D1² / π/4.D2² ) = √( )
( D1² / D2² ) = √( 
) since second is double of first
so
( D1² / D2² ) = √( 
)
3² / D2² = √2
D2²√2 = 9
D2² = 9/√2
D2² = 9 / 1.4142
D2² = 6.364
D2 = √ 6.364
D2 = 2.52 in
Therefore, the diameter of the second pipe is 2.52 in
Answer:
far from the speaker the intensity drops to 85 dB.
Explanation:
In the equation for the Decibel scale
The ratio of the intensities can be written as
And since
and
,
meaning
Putting this into equation (1), we get:
Now, if the intensity is 100 dB when the distance is 5 meters, we have:
by taking both sides to the exponent:
Now equation (2) becomes
when the intensity level is 85 dB we have
take both sides to exponents and we get:
Thus, far from the speaker the intensity drops to 85 dB.
