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agasfer [191]
3 years ago
5

Calculate the density of an object with a volume of 18m3 and a mass of 3.5kg?

Physics
1 answer:
jasenka [17]3 years ago
3 0
0.19
Explanation:you will divide 3.5 and 18
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When two or more forces act on an object at the same time what are they called
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Unbalanced forces is what they are called

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1. A brick and a peanut are dropped of the roof of a house at the same time, which
iris [78.8K]

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Explanation:

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If the distance d (in meters) traveled by an object in time t (in seconds) is given by the formula d=a+bt2, the si units of a an
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The unit of d is in meter and t is in seconds.

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if the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?
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7 0
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Read 2 more answers
A 600kg car is moving at 5 m/s to the right and elastically collided with a stationary 900 kg car. What is the velocity of the 9
11111nata11111 [884]

Answer:

\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}

Explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

m_{1} v_{1}=m_{2} v_{2}

\mathrm{m}_{1} \text { and } \mathrm{m}_{2} \text { are masses of the object }

\mathrm{v}_{1} \text { velocity before the collision }

\mathrm{v}_{2} \text { velocity after the collision }

\mathrm{m}_{1}=600 \mathrm{kg}

\mathrm{m}_{2}=900 \mathrm{kg}

\text { Velocity before the collision } v_{1}=5 \mathrm{m} / \mathrm{s}

600 \times 5=900 \times v_{2}

3000=900 \times v_{2}

\mathrm{v}_{2}=\frac{3000}{900}

\mathrm{v}_{2}=3.3 \mathrm{m} / \mathrm{s}

\mathrm{v}_{2} \text { velocity after the collision is } 3.3 \mathrm{m} / \mathrm{s}

5 0
3 years ago
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