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3 years ago

Calculate the density of an object with a volume of 18m3 and a mass of 3.5kg?

Physics

1 answer:

jasenka [17]3 years ago

3 0

0.19
Explanation:you will divide 3.5 and 18

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The vector position of an object is given by r what is the torque acting on the object about the origin when a force f = (−12.5i

attashe74 [19]

Let the vector position of the object in the (x-y) plane be
$\vec{r} = x \hat{i} + y \hat{j}$

The applied force is
$\vec{f} = -12.5 \hat{i}
$

By definition, the applied torque is
$\vec{T} = \vec{r} \times \vec{f} = (x\hat{i} + y\hat{j}) \times (-12.5y \hat{i}) = 12.5\hat{k}$

Answer: $12.5y \, \hat{k}$

7 0

4 years ago

What is the force that causes a 8 kg object to accelerate at 4 m/s^2

Vitek1552 [10]

Answer: F = 32 N

Explanation:

F= m x a

m = 8 kg

a = 4 m/s²

F = 8 kg x 4 m/s² = 32 kg m /s² = 32 Newton

5 0

3 years ago

Suppose that 2.5 moles of an ideal gas are in a chamber in equilibrium at temperature 310 K and volume 0.5 m3. 1) What is the pr

Basile [38]

Answer:

The pressure in the chamber are of p= 0.127 atm.

Explanation:

n= 2.5 moles

T= 310 K

V= 0.5 m³ = 500 L

R= 0.08205746 atm. L /mol . K

p= n*R*T/V

p= 0.127 atm

3 0

3 years ago

John walks to school in the morning then walks home for lunch. The school is 250 meters directly north of his house. After lunch

sp2606 [1]

Answer:

300 meters south

Explanation:

Displacement is a vector that connects the initial position with the final position of the motion.

In order to find the net displacement, we must add the distance covered in each part of the motion, considering the proper sign. We take the following convention:

North --> +

South --> -

So, John made the following trips:

Home --> school: 250 m north = +250

School --> home: 250 m south = -250

Home --> school: 250 m north = +250 m

School --> friend's house: 550 m south = -550 m

So, the net displacement is

d = +250 -250 +250 -550 = -300

So, 300 m south.

8 0

3 years ago

Read 2 more answers

The weight of an object on Earth is 350 newtons. On Mars, the same object would weigh 134 newtons. What is the acceleration due

lys-0071 [83]

Object mass =mk<span>g
</span>acceleration due to gravity of Mars = gm m/ $8^{2}$
acceleration due to gravity on Earth ge=−9.8 m/ $8^{2}$
weight of an object on Earth=m×ge=350N
weight of an object on Mars=m×gm=134<span>N
</span>

m x gm = 134

m x ge = 350

gm = 134/350 x 9.8 m/ $8^{2}$ = 3.752 m/ $8^{2}$

4 0

3 years ago