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jeyben [28]
2 years ago
15

Name an element in the same period as rubidium

Physics
1 answer:
Artyom0805 [142]2 years ago
5 0

Answer: Potassium(K)

Explanation:

its an alkali metal placed under sodium and its over rubidium, its also the first element of period 4

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A 5- kg object experiences forces as shown in the diagram. Which statement best describes the motion of the object
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A ball is kicked at an angle of 35 degrees with the ground. What should be the initial velocity of the ball so that it hits a ta
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18.5 M/S

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8. (Liquids, Gas) have no definite shape, and no definite volume.<br> A)Liquid<br> B)Gas
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"Response to stimulus" refers to
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3 years ago
A 60kg skateboarder starts up a 20° slope at 5m/s then falls and slides up the hill on his knee pads. The coefficient of kinetic
klasskru [66]
2.0 meters  The skateboarder has 2 forces acting upon him to slow him down. The forces are friction, and climbing against the gravitational acceleration. So let's calculate the magnitude of these forces to see how fast he's decelerated.  The coefficient of kinetic friction is a multiplier to use against the normal force of the object. We can calculate the normal force by multiplying the mass of the object by the local gravitational acceleration and the cosine of the angle. So Df = 60 kg * 9.8 m/s^2 * cos(20°) * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 60 kg * 9.8 m/s^2 * 0.939692621 * 0.30 Df = 165.7617783 kg*m/s^2 Df = 165.7617783 N  
The second amount of force is that caused by gravitational acceleration while climbing. That is determine by the amount of height gained for every meter along the slope. We can calculate that using the sine of the angle. So 
Dg = 60 kg * 9.8 m/s^2 * sin(20°)
 Dg = 60 kg * 9.8 m/s^2 * 0.342020143
 Dg = 201.1078443 kg*m/s^2
 Dg = 201.1078443 N
 
 So the amount of force decelerating the skateboarder is:
 F = Df + Dg
 F = 165.7617783 N + 201.1078443 N
 F = 366.8696226 N
 
 Now let's determine how much kinetic energy needs to be dissipated. The equation is
 E = 0.5 MV^2 
 So we'll substitute the known values and calculate
 E = 0.5 MV^2
 E = 0.5* 60 kg * (5 m/s)^2
 E = 0.5* 60 kg * 25 m^2/s^2
 E = 750 kg*m^2/s^2
 E = 750 J 
 Now let's divide the energy by the force.
 750 kg*m^2/s^2 / 366.8696226 kg*m/s^2 = 2.04432298 m
  Rounding to 2 significant figures gives a distance of 2.0 meters.
4 0
3 years ago
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