From the ohms law resistance is given by dividing the amount of current by the potential difference (voltage). In a circuit resistors may be arranged in series or parallel which determines the total effective resistance of the circuit depending on the arrangement used.
When resistance are in parallel we apply the formula 1/Rt=1/R1 +1/R2 where Rt is the total resistance, R1 resistance of the first resistor and R2 the resistance of the second resistor.
therefore, 1/Rt = 1/10 +1/10 =2/20 which when simplified is 1/10, therefore 1/Rt is 1/10, to get Rt we do the reciprocal to get 10 ohms.
Therefore the effective resistance of the combined resistors in parallel is 10 ohms
(a). The power of the candy bar is,
The time taken to play on 800 kJ energy of the candy bar is,
where E is the energy.
Substituting the known values,
As 1 minute is equal to 60 seconds,
Thus,
Thus, the time taken to play tennis on the 800 kJ energy is 30.3 minutes.
(b). By doing the exercise, the process of digestion of food inside our body increases. Thus, the exercise does not helps us to burn the calories. But it helps us to diggest the heavy meal like candy bar easily.
The time taken to digest the canndy bar or to utilise its energy is large because it takes a lot of time to burn small amount of food and make it digest quickly.
With another person on student A’s side. I’m sorry if I wasn’t able to help. Im trying my best from the information given. :)
Answer:
rods are more light sensitive than cones.
Explanation:
There are two types of photo receptors in retina of our eyes. 1 Rods and 2 Cones. Rods are about 120 million and they are more sensitive then the cones. But the rods are not sensitive to color. Cones help us in seeing the color and there are about 6 to 7 million cones that provide color sensitivity to our eyes. That is why in the dark or where their are dim levels of illumination rods provide us scotopic vision. Because rods are more light sensitive then the cones.
Answer:
Approximately 
and approximately 
.
Explanation:
Let 
and 
denote the capacitance of these two capacitors.
When these two capacitors are connected in parallel, the combined capacitance will be the sum of and . (Think about how connecting these two capacitors in parallel is like adding to the total area of the capacitor plates. That would allow a greater amount of charge to be stored.)
.
On the other hand, when these two capacitors are connected in series, the combined capacitance should satisfy:
.
(Consider how connecting these two capacitors in series is similar to increasing the distance between the capacitor plates. The strength of the electric field (
) between these plates will become smaller. That translates to a smaller capacitance if the amount of charge stored 
stays the same.)
The question states that:
, and
.
Let the capacitance of these two capacitors be 
and 
. The two equations will become:
.
From the first equation:
.
Hence, the 
in the second equation here can be replaced with 
. That equation would then become:
.
Solve for 
:
.
.
.
Solve this quadratic equation for :
or 
.
Substitute back into the equation for :
In other words, these two capacitors have only one possible set of capacitances (even though the previous quadratic equation gave two distinct real roots.) The capacitances of the two capacitors would be approximately 
and approximately (both values are rounded to two significant digits.)
, or