When a spring is compressed, the energy changes from kinetic to potential. Which best describes what is causing this change?

Physics

2 answers:

Dafna11 [192]3 years ago

6 0

Answer:Work

Explanation:

When a spring is compressed the energy changes from kinetic to potential energy as Energy cannot be destroyed but can be transformed from one form to another.

This can be best explained with the help of work. Suppose a block with certain kinetic energy comes in contact to the spring its kinetic energy changes to Potential Energy of the spring or we can say that its Kinetic Energy is converted to Potential energy as the block does work on spring.

Block compresses the spring by changing its length and it requires some work which is equal to change in its Potential Energy of spring.

skad [1K]3 years ago

4 0

Answer:

A) Work

Explanation:

I just took the test

You might be interested in

Charge q is accelerated starting from rest up to speed v through the potential difference V. What speed will charge q have after

adoni [48]

Answer: v = $1.19 * 10^{6} m/s$

Explanation: q = magnitude of electronic charge = $1.609 * 10^{-19} c$

mass of an electronic charge = $9.10 * 10^{-31} kg$

V= potential difference = 4V

v = velocity of electron

by using the work- energy theorem which states that the kinetic energy of the the electron must equal the work done use in accelerating the electron.

kinetic energy = $\frac{mv^{2} }{2}$ , potential energy = qV

hence, $\frac{mv^{2} }{2} = qV$

$\frac{9.10 *10^{-31} * v^{2} }{2} = 1.609 * 10^{-16} * 4\\\\\\\\9.10*10^{-31} * v^{2} = 2 * 1.609 *10^{-16} * 4\\\\\\9.10 *10^{-31} * v^{2} = 1.287 *10^{-15} \\\\v^{2} = \frac{1.287 *10^{-15} }{9.10 *10^{31} } \\\\v^{2} = 1.414*10^{15} \\\\v = \sqrt{1.414*10^{15} } \\\\v = 1.19 * 10^{6} m/s$