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Black_prince [1.1K]
3 years ago
13

(100 points!!!) Martin has a very limited wardrobe. He has four pairs of pants: one blue, one green, one tan, and one white. He

also has five shirts: two blue, one white, one green and one green and tan striped.
a. Create a probability table representing Martin's possible outfits. put it on paper or something you could write in, upload the pic on this question on brainly

b. If Marten closes his eyes and picks a shirt and a pair of pants at random, what is the probability he will be wearing

i. green pants and a blue shirt?
ii. tan pants and a white shirt?
iii. white pants and white shirt?​
Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
7 0

Answer:

Step-by-step explanation:

i. <u>1/10</u>

ii. <u>1/20</u>

iii. <u>1/20</u>

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The rent for an office space is $674.30 per month. The office is 306 1/2 square feet in area.What is the monthly cost per square
Rufina [12.5K]
The answer is B because 674.30 divided by 306.5 equals 2.2 or $2.20
3 0
3 years ago
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6 0
3 years ago
Read 2 more answers
Solve for x: 12-2x=-2(y-x)
a_sh-v [17]
12 - 2x = -2(y - x)

12 - 2x = -2y - (-2x)

12 - 2x = -2y + 2x

12 - 2x - 2x = -2y + 2x - 2x

12 - 4x = -2y

12 - 12 - 4x = -2y - 12

-4x = -2y - 12

-4x/4 = -2y/4 - 12/4

-x = -0.5y - 3

-x/-1 = -0.5y/-1 - 3/-1

x = 0.5y + 3

or

x = 3 + 0.5y
3 0
3 years ago
P viuen
Alex787 [66]
Hello what do you exactly need help for
3 0
3 years ago
I need help please ASAP full points
kotegsom [21]

The best way to solve this problem is with a simple equation: part = percent (in decimal form) x whole

In this problem, we're trying to solve for the <em>whole </em>amount that the camera can hold, so we'll assign that the variable w.

We can use the information they gave us - 96 is the <em>part</em>, and 24% is the percent. We'll convert that to decimal form - 0.24

Then, we just plug these values back into the above equation:

96 = 0.24w

Divide both sides by 0.24 to get w on it's own, and you have your answer!

400 = w

Therefore, the memory card can hold up to 400 pictures.


Note: this equation is <em>super </em>helpful. It's good to have on hand for any problem involving percents, because you can solve for the part, percent, or whole depending on the problem.

4 0
3 years ago
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