#1. Given the binomials (x - 2), (x - 1), (x + 2), and (x - 4), which one is a factor of f(x) = x3 + 7x2 + 14x + 8? (x - 2) (x -
1) (x + 2) (x - 4) Given the binomials (x + 1), (x + 4), (x - 5), and (x - 2), which one is a factor of f(x) = 3x3 - 12x2 - 4x - 55? (x + 1) (x + 4) (x - 5) (x - 2) #2. What is the f of x over the g of x when f(x) = 6x3 - 19x2 + 16x - 4 and g(x) = x - 2? 6x2 - 7x + 2/3x2 - 9x + 8/ 6x2 - 7x + 2 - 8 over the quantity of x minus 2/3x2 - 9x + 8 - 8 over the quantity of x minus 2
#3. What is the f of x over the g of x when f(x) = 6x3 - 19x2 + 16x - 4 and g(x) = x - 2? #4.What is the quotient when -3x3 + 5x + 14 is divided by x - 2? -3x2 - 6x - 7/- 3x2 - x + 12/-3x2 + 6x - 7 + 28 over the quantity of x minus 2/
-3x2 - x + 12 + 28 over the quantity of x minus 2.
#4. What is the quotient when x3 - 5x2 + 2x + 5 is divided by x - 2?
x2 - 3x - 4/ x2 - 7x + 16/x2 - 3x - 4 - 3 over the quantity of x minus 2
#2 f(x) / g(x) = (</span>6x3 - 19x2 + 16x - 4) / (x - 2) This can be solved by factoring the numerator, by synthetic division or using the remainder theorem.
The result is: 6x^2 - 7x + 2 or (x - 2/3)(x - 1/2)
#3 same with #2
#4 (x3 - 5x2 + 2x + 5) / (x - 2) Again, this can be solved by a number of methods, the result is: x2 -3x - 4 - (3/x-2)
