If sam ran 2hrs on the treadmill and ran Sarah ran 2/3 how many did john do?
2 answers:
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ANSWER
and
e have
EXPLANATION
Let us make y the subject and call it equation (2)
We put equation (2) in to equation (1)
Simplify to get,
Divide both sides by 31,
We put this value in to equation (2) to get,
We collect LCM to obtain,
This question is incomplete, the microstates table is left out which will be uploaded along this answer;
Answer:
a) the required is 65.6%
b) the required time is 4.2666 hrs
Step-by-step explanation:
using the microstates from the table in the diagram;
a)
the percent times the above any of the above microstates occurs is;
% (6 heads and 4 tails, 5 heads and 5 tails, 4 heads and 6 tails)
= ((210 + 252 + 210)/1024) × 100
= 0.6562 × 100
= 65.6%
Therefore the required is 65.6%
b)
the probability of getting 10 heads and 0 tail or 0 tail head and 10 tails is;
p( 10H, 0T or 0H, 10T = 2/1024
= 1/512
so on average, it will take 512 trails or at a rate of 2 trials/min, 256 mim in hours;
(256 min) ( 1h/60min) = 4.2666 hrs
Therefore the required time is 4.2666 hrs
