The force needed to stretch the steel wire by 1% is 25,140 N.
The given parameters include;
- diameter of the steel, d = 4 mm
- the radius of the wire, r = 2mm = 0.002 m
- original length of the wire, L₁
- final length of the wire, L₂ = 1.01 x L₁ (increase of 1% = 101%)
- extension of the wire e = L₂ - L₁ = 1.01L₁ - L₁ = 0.01L₁
- the Youngs modulus of steel, E = 200 Gpa
The area of the steel wire is calculated as follows;

The force needed to stretch the wire is calculated from Youngs modulus of elasticity given as;


Thus, the force needed to stretch the steel wire by 1% is 25,140 N.
Learn more here: brainly.com/question/21413915
Answer:
u = 10.63 m/s
h = 1.10 m
Explanation:
For Take-off speed ..
by using the standard range equation we have

R = 9.1 m
θ = 26º,
Initial velocity = u
solving for u



u = 10.63 m/s
for Max height
using the standard h(max) equation ..



h = 1.10 m
Answer:
27 m/s
Explanation:
Given:
v₀ = 15 m/s
a = 3 m/s²
t = 4 s
Find: v
v = at + v₀
v = (3 m/s²) (4 s) + (15 m/s)
v = 27 m/s
Answer:
1.34352 kg
Explanation:
= Mass of water falling = 1 kg
h = Height of fall = 0.1 km
= Change in temperature = 0.1
c = Specific heat of water = 4186 J/kg K
g = Acceleration due to gravity = 9.81 m/s²
= Mass of water in the vessel
Here the potential energy will balance the internal energy

Mass of the water in the vessel is 1.34352 kg