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3 years ago

A longitudinal wave is transporting energy from south to north. the particles in the medium will move...

Physics

1 answer:

Alisiya [41]3 years ago

6 0

Answer:

north only

Explanation:

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What is the characteristic of a Matrix Transpose

yulyashka [42]

Answer:

columns are converted into rows , and rows are converted into columns

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4 years ago

Kyle, a 95.0 kg football player, leaps straight up into the air (with no horizontal velocity) to catch a pass. He catches the 0.

babymother [125]

Answer:

The initial speed of the ball was 26.2 m/s

Explanation:

When the football player is in the air at his maximum height the vertical component of velocity is zero, To obtain the horizontal velocity when the player catches the ball we need to apply the linear momentum conservation theorem:

$m_1*v_{o1}+m_2*v_{o2}=m_t*v_f\\0.430kg*(v)+m_2*(0)=mt*vt$

we need to obtain the time taken to go down.

$y=Y_o+v_o*t-\frac{1}{2}g*t^2\\\\0=0.589-4.9t^2\\solving:\\t_1=0.346s\\$

We have a horizontal displacement and the time taken to stop, so:

$v_f=\frac{d}{t}=\frac{0.0409m}{0.346s}=0.118m/s$

so:

$0.430kg*(v)+m_2*(0)=(m1+m2)*vt\\v=\frac{(95.0kg+0.430kg)*0.118m/s}{0.430kg}\\\\v=26.2m/s$

8 0

3 years ago

Waves that move by replacing particles

AnnyKZ [126]

What’s the question

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3 years ago

An airplane is flying in a horizontal circle at a speed of 92.1 m/s. The 55.6 kg pilot does not want his radial acceleration to

Fudgin [204]

Answer:

r = 102.43 m

Explanation:

Newton's second law for this case is

F = ma

Where the acceleration is centripetal

a = v² / r

r = v² / a

They indicate that the radial acceleration is 8.45 g

r = v² / 8.45 g.

r = 92.1² / 8.45 9.8

r = 102.43 m

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3 years ago

plz help me with hw A bus of mass 1000 kg moving with a speed of 90km/hr stops after 6 sec by applying brakes then calculate the

Lelechka [254]

Answer:

Mass, M = 1000 kg

Speed, v = 90 km/h = 25 m/s

time, t = 6 sec.

Distance:

${ \tt{distance = speed \times time }} \\ { \tt{distance = 25 \times 6}} \\ { \tt{distance = 150 \: m}}$

Force:

${ \tt{force = mass \times acceleration}} \\ { \bf{but \: for \: acceleration : }} \\ from \: second \: equation \: of \: motion : \\ { \bf{s = ut + \frac{1}{2} {at}^{2} }} \\ \\ { \tt{150 = (0 \times 6) + ( \frac{1}{2} \times a \times {6}^{2} ) }} \\ \\ { \tt{acceleration = 8.33 \: {ms}^{ - 2} }} \\ \\ { \tt{force = 1000 \times 8.33}} \\ { \tt{force = 8333.3 \: newtons}}$

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3 years ago