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3 years ago

Select all the correct answers.

Physics

2 answers:

Sergeu [11.5K]3 years ago

8 0

Force is transferred from the moving ball to the stationary ball.

IrinaK [193]3 years ago

5 0

The moving ball transfers it’s energy and hits the stationary ball. Slowing the moving ball and speeding up the stationary ball.

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A particle (charge 7.5 μC) is released from rest at a point on the x axis, x = 10 cm. It begins to move due to the presence of a

zysi [14]

Answer:

The correct answer is option 'D': 1.2 Joules

Explanation:

Since the energy associated with the electric field is conservative thus we conclude that the

Kinetic energy of the moving particle equals the change in electrostatic potential energy.

For the initial case

$U_1=qV$

Now V associated with the 2.0μC charge is

$V=\frac{}{4\pi \epsilon _o\cdot r}$

Applying the given values we get

$U_1=7.5\times 10^{-6}\times \frac{2.0\times 10^{-6}}{4\pi \times 8.85\times 10^{-12}\times 0.1}\\\\\therefore U_1=1.35J$

When the moving charge reaches x = 1.0 meter the energy becomes

$U_2=7.5\times 10^{-6}\times \frac{2.0\times 10^{-6}}{4\pi \times 8.85\times 10^{-12}\times 1}\\\\\therefore U_2=0.135J$

Thus the change in energy is $U_1-U_2=1.35-0.135=1.2J$

3 0

3 years ago

HELP ME PLEASE 20 POINTS

anastassius [24]

The answer is C. I searched it up and people keep on saying that it's B, which is incorrect. I found another question on Brainly where someone said that C was the answer and the person who asked the question said "Correct, thanks."

6 0

2 years ago

What is the maximum speed with which a 1200-kg car can round a turn of radius 90.0 m on a flat road if the coefficient of fricti

RideAnS [48]

Answer:

Maximum speed of the car is 26.56 m/s.

Explanation:

Given that,

Mass of the car, m = 1200 kg

Radius of the curve, r = 90 m

The coefficient of friction between tires and the road is 0.8.

We need to find the maximum speed of the car. On the circular curve, the centripetal force is balanced by the force of friction. So,

$\dfrac{v^2}{r}=\mu g\\\\v=\sqrt{\mu gr} \\\\v=\sqrt{0.8\times 9.8\times 90} \\\\v=26.56\ m/s$

So, the maximum speed of the car is 26.56 m/s.

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3 years ago

A ball is dropped from a height of 6ft. whenever it hits the ground it bounces back to half its original height. what is the tot

Lady bird [3.3K]

The ball has travelled a total distance of 18 feet after dropping and rebounding.

After being dropped for the first time, the ball will rebound to a height of 3 feet as it returns to half its original height. The geometric series formed by the total distance travelled while falling and rebounding has a common ratio,

r = 0.5

6 ft + 3 ft = 9 ft will be the first term in the series

For the sum formula S = $\frac{a}{1-r}$ ,