answer is down hera
Select all the correct answers.
2 answers:
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Answer:
- 91499.95 V
Explanation:
Let the mid point is P.
qA = 3.4 pC = 3.4 x 10^-12 C
qB = - 6.10 micro Coulomb = - 6.10 x 10^-6 C
AB = 1.20 m
AP = BP = 0.6 m
Let the potential at P due to the charge at A is VA and the potential at P due to the charge at B is VB.
The potential at P is V
V = VA + VB
V = 0.051 - 91500
V = - 91499.95 V
Answer:
240.1m
Explanation:
Given parameters:
Time taken to hit the ground = 7s
Unknown:
Height of the cliff = ?
Solution:
To solve this problem, we use the right motion equation expressed below:
S = ut + gt²
S is the height of the cliff
u is the initial velocity = 0m/s
g is the acceleration due to gravity = 9.8m/s²
t is the time taken
Now, insert the parameters and solve the problem;
S = (0 x 7) + ( x 9.8 x 7²)
S = 240.1m