Incomplete question as the charge density is missing so I assume charge density of 3.90×10^−12 C/m².The complete one is here.
An electron is released from rest at a distance of 0 m from a large insulating sheet of charge that has uniform surface charge density 3.90×10^−12 C/m² . How much work is done on the electron by the electric field of the sheet as the electron moves from its initial position to a point 3.00×10−2 m from the sheet?
Answer:
Work=1.06×10⁻²¹J
Explanation:
Given Data
Permittivity of free space ε₀=8.85×10⁻¹²c²/N.m²
Charge density σ=3.90×10⁻¹² C/m²
The electron moves a distance d=3.00×10⁻²m
Electron charge e=-1.6×10⁻¹⁹C
To find
Work done
Solution
The electric field due is sheet is given as
E=σ/2ε₀
Now we need to find force on electron
Now for Work done on the electron
Answer:
W = 270.9 J
Explanation:
given,
F(x) = (12.9 N/m²) x²
work = Force x displacement
dW = F .dx
the push-rod moves from x₁= 1 m to x₂ = 4 m
integrating the above
![W = 12.9\times [\dfrac{x^3}{3}]_1^4 dx](https://tex.z-dn.net/?f=W%20%3D%2012.9%5Ctimes%20%5B%5Cdfrac%7Bx%5E3%7D%7B3%7D%5D_1%5E4%20dx)
`![W = 12.9\times [\dfrac{4^3}{3}-\dfrac{1^3}{3}] dx](https://tex.z-dn.net/?f=W%20%3D%2012.9%5Ctimes%20%5B%5Cdfrac%7B4%5E3%7D%7B3%7D-%5Cdfrac%7B1%5E3%7D%7B3%7D%5D%20dx)
W = 270.9 J
work done by the motor is W = 270.9 J
Answer:
more time to change the momentum of falling rocks
Explanation:
Momentum is related to "mass in motion." So, if an object is moving, then it has momentum as it has its mass in motion. The amount of momentum is dependent upon how much and how fast the object is moving.
If an object is moving slowly, it means that the object is losing momentum.
Nets used to catch falling boulders on the side of rocky hillside roadways are more effective than rigid fences because their breakage is reduced by more time to change the momentum of falling rocks.
Answer:
Yes
Explanation:
Newton's third law
For every action, there is an equal and opposite reaction.
SO if the apple is falling 9.8 m/s2 then the same force is pushing against it.
Hope this helps
