A. The vibrations of the fields are perpendicular to the direction in which the wave moves.
Answer:
Percentage change in tension is 3.8%
Explanation:
We have given initially frequency
= 440 Hz
Let tension in the string at this frequency is 
Now second frequency is 
Frequency in string is given by

From the relation we can say that


Percentage change in tension is equal to
%
So percentage change in tension is 3.8%
Answer:
The points 2 and 4 should be connected.
Explanation:
To complete the circuit, we need to connect the two points which when connected, encompass the battery and the bulb in the circuit. The points 2 and 4 do the job, since they connect the terminal of the battery and the terminal of the bulb, and thus complete the circuit.
Therefore, the choice C is correct.
Explanation:
Let h is the height of the plane above ground. x is the horizontal distance between the ground and the airport. Let s(t) is the distance between the plane and the airport. So,
...........(1)
Given, h = 4, x = 40 and s(t) = -20 mph
Differentiate equation (1) wrt t


When x = 40, 



So, the speed of the airplane is 241.14 m/s. Hence, this is the required solution.