Answer:
Step-by-step explanation:
By applying the concept of calculus;
the moment of inertia of the lamina about one corner 
is:
where :
(a and b are the length and the breath of the rectangle respectively )
![I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Bbx%5E3%7D%7B3%7D%2B%20%5Cfrac%7Bb%5E3x%7D%7B3%7D%5D%5E%20%7B%5E%20a%7D%20_%7B_0%7D)
![I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]](https://tex.z-dn.net/?f=I_%7Bcorner%7D%20%3D%20%20%5Crho%20%5B%5Cfrac%7Ba%5E3b%7D%7B3%7D%2B%20%5Cfrac%7Bab%5E3%7D%7B3%7D%5D)
Thus; the moment of inertia of the lamina about one corner is
1. When there are two events that need to happen, we must multiply the probability of each event happening.
Shawn losing to Mike: 5/8 chance
Shawn losing to Tim: 2/7 chance
5/8 × 2/7 = 10/56 = 5/28
There's a 5/28 chance of Shawn losing to Mike and Tim.
I don't know #2, sorry :/
Hope this helps!
<em>《</em><em>°</em><em>♡</em><em> </em><em>i think that the answer to this question is -5 1/3</em><em> </em><em>(</em><em>-16</em><em>/</em><em>3</em><em>)</em><em> </em><em>hope this helps!</em><em> </em><em>♡</em><em>°</em><em>》</em>
A energy can never be completely used up. When something "runs out of energy" it just runs out of use able energy that can be used to do the task that it was doing in the first place so it is now useless to that object and it must move on to be used for a different object.
