A circular coil of 216 turns has a radius of 2.32 cm. (a) Calculate the current that results in a magnetic dipole moment of magn itude 2.89 A·m2. (b) Find the maximum magnitude of the torque that the coil, carrying this current, can experience in a uniform 46.0 mT magnetic field.
1 answer:
Answer:
(a) 7.92 A
(b) 0.133 Nm
Explanation:
N = 216
r = 2.32 cm = 0.0232 m
(a) M = 2.89 Am^2
M = N i A
Where, A be the area of the coil and i be the current in the coil
2.89 = 216 x i x 3.14 x 0.0232 x 0.0232
i = 7.92 A
(b) B = 46 mT = 0.046 T
Torque, τ = M B Sin 90
τ = 2.89 x 0.046 x 1 = 0.133 Nm
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